This is just simple. For example you have a plane of the form x=a, then you just substitute x with a, and you'll get an equation with y and z only, hence you have a 2-d trace of the intersection. It is just similar for y=b and z=c.
(1) At z=1.5, 2x^2 + 5y^2 + 1.5^2 = 4
2x^2 + 5y^2 = 1.75
Now you have an ellipse in the z=1.5 plane as your trace.
(2) At x=1, 2(1)^2 + 5y^2 + z^2 = 4
5y^2 + z^2 = 2
Now you have an ellipse in the x=1 plane as your trace.
(3) At z=0, 2x^2 + 5y^2 + (0)^2 = 4
2x^2 + 5y^2 = 4
Now you have an ellipse in the z=0 plane as your trace.
(4) At y=0, 2x^2 + 5(0)^2 + z^2 = 4
2x^2 + z^2 = 4
Now you have an ellipse in the y=0 plane as your trace.
Answer:
x=1 y=12
Step-by-step explanation:
Answer:
m=4/-3
Step-by-step explanation:
the equation for slope (m) when given two points is (y2-y1)/(x2-x1)
we are given the points (9,3) and (6,7)
we can label the points:
x1=9
y1=3
x2=6
y2=7
now substitute into the equation
m=(7-3)/(6-9)
subtract
m=4/-3
the slope is 4/-3
hope this helps!
So that equation was definitely correct...
When you expand the equation in the bracket you'll find out that you'll get a^6 + 4a^4 + !6a^2 - 4a^4 - 16a^2 -64. then your final result will be a^6 - 64
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Answer:
not all of them are proportional because they do not all equal the same.
Step-by-step explanation:
