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2 years ago

4/5 and 3/7 plz help

Mathematics

1 answer:

Anika [276]2 years ago

5 0

Answer:

What are you trying to ask

Step-by-step explanation:

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Determine two coterminal angles (one positive and one negative) for each angle. Give your answers in radians. (Enter your answer

vagabundo [1.1K]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

In point a:

$\to \frac{5 \pi }{6}$

calculating a positive coterminal angle:

$\to \frac{5 \pi }{6} + 2 \pi \\\\ \to \frac{5 \pi +12 \pi }{6} \\\\ \to \frac{17 \pi }{6} \\\\$

calculating negative coterminal angle:

$\to \frac{5 \pi }{6} -2\pi \\\\ \to \frac{5 \pi - 12 \pi }{6} \\\\ \to \frac{ - 7 \pi }{6} \\\\$

In point b:

$\to \frac{-9 \pi }{4}$

calculating a positive coterminal angle:

$\to \frac{ -9 \pi }{4} + 2 \pi \ \ = \frac{-9 \pi + 8 \pi }{4} \\\\$

$\to \frac{ - \pi }{4} + 2 \pi \ \ = \frac{- \pi + 8 \pi }{4} \\\\$

$= \frac{ 7 \pi}{4}$

calculating a negative coterminal angle:

$\to \frac{ -9 \pi }{4} - 2 \pi \\\\ \to \frac{-9 \pi - 8 \pi }{4} \\\\ \to \frac{-17 \pi }{4}$

3 0

3 years ago

The triangle and the trapezoid have the same area. Base b2 is twice the length of base b1. What are the lenghts of the bases of

Sati [7]

Answer:

<h2>The lengths of the bases of the trapezoid:</h2><h2>42/h cm and 84/h cm.</h2>

Step-by-step explanation:

The formula of an area of a triangle:

$A=\dfrac{bh}{2}$

b - base

h - height

We have b = 21cm, h = 6cm.

Substitute:

$A=\dfrac{(21)(6)}{2}=63\ cm^2$

The formula of an area of a trapezoid:

$A=\dfrac{b_1+b_2}{2}\cdot h$

b₁, b₂ - bases

h - height

We have b₁ = 2b₂, therefore b₁ + b₂ = 2b₂ + b₂ = 3b₂.

The area of a triangle and the area of a trapezoid are the same.

Therefore

$\dfrac{3b_2}{2}\cdot h=63$ multiply both sides by 2

$3b_2h=126$ divide both sides by 3

$b_2h=42$ divide both sides by h

$b_2=\dfrac{42}{h}$

$b_1=2b_2\to b_1=2\cdot\dfrac{42}{h}=\dfrac{84}{h}$

8 0

2 years ago

Read 2 more answers

Find the x-intercept and y-interceppt of each graph

Paha777 [63]

Answer:

11.) y-int:(0,1); x-int:(1,0)

12.) y-int:(0,8); x-int:(4,0)

13.) y-int:(0,-9); x-int:(-3,0)

14.) y-int:(0,-5); x-int:(-2.5,0)

Step-by-step explanation:

For each equation, first you have to graph it. Then to find the y-intercept, you mark and check where your line of your equation intersects the y-axis. To find the x-intercept, you mark and check where the line of your equation intersects the x-axis. The y-intercept always will have the coordinates of x=0 and the x-intercept always will have the coordinates of y=0.

5 0

2 years ago

In right △ABC , the right angle is at C, m∠A=30∘ , and AC=5√ 5 units.

Makovka662 [10]

Answer:

5 $\sqrt{15}$ +5 $\sqrt{5}$