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Serga [27]
2 years ago
7

Explain how you would find the least impossible number of rows in the auditorium

Mathematics
1 answer:
Anna007 [38]2 years ago
4 0
You would find the least possible rows in the auditorium by multiplying 8 by 70 and the answer would be 560 seats in the auditoturim. This would be correct because Kayla knows that there are at least 70 rows (the least amount of rows).

I hope this helped you 

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(-2)(4) - 7^2 help me
wlad13 [49]

Answer:

(-2)(4) - 7^2

-8-7^2

-8-49

=-57

Step-by-step explanation:

4 0
3 years ago
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Gil is reading a book that has 276 pages.he already read some of it last week. He plans to read 20 pages tomorrow. By then he wi
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Last week Gill read 164 of the 276 pages of the book.
                                                                   hope this helped :)








7 0
3 years ago
NEED HELP ASAP THIS IS A TEST<br><br> will mark brainlest <br><br> NO LINKS
Nataly_w [17]
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From quizlet made from balletskye20 with 16 terms
8 0
2 years ago
Which expressions are equivalent to 1−2x−1.7 ?
siniylev [52]

Step-by-step explanation:

if there are no typos, then the second and the fourth answers are correct.

1 - 1.7 = -0.7 or -2×0.35

-2x = -2(x)

8 0
2 years ago
Confidence Interval Mistakes and Misunderstandings—Suppose that 500 randomly selected recent graduates of a university were as
kvv77 [185]

Answer:

The correct 95% confidence interval is (8.4, 8.8).

Step-by-step explanation:

The information provided is:

n=500\\\bar x=8.6\\\sigma=2.2

(a)

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The 95% confidence interval for the average satisfaction score is computed as:

8.6 ± 1.96 (2.2)

This confidence interval is incorrect.

Because the critical value is multiplied directly by the standard deviation.

The correct interval is:

8.6\pm 1.96 (\frac{2.2}{\sqrt{500}})=8.6\pm 0.20=(8.4,\ 8.6)

(b)

The (1 - <em>α</em>)% confidence interval for the parameter implies that there is (1 - <em>α</em>)% confidence or certainty that the true parameter value is contained in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true there is a 95% confidence that the true parameter value is contained in this interval.

The mistake is that the student concluded that the sample mean is contained in between the interval. This is incorrect because the population is predicted to be contained in the interval.

(c)

The (1 - <em>α</em>)% confidence interval for population parameter implies that there is a (1 - <em>α</em>) probability that the true value of the parameter is included in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true mean satisfaction score is contained between 8.4 and 8.8 with probability 0.95 or 95%.

Thus, the students is not making any misinterpretation.

(d)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

In this case the sample size is,

<em>n </em>= 500 > 30

Thus, a Normal distribution can be applied to approximate the distribution of the alumni ratings.

7 0
3 years ago
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