Ask question

Ask question

All categories

3 years ago

12

MK and ML are tangent to circle J. If MK = 6x – 15 and ML = 2x + 9, find x. * am i right?? * --> provide details if i'm wrong

.

1 answer:

Veseljchak [2.6K]3 years ago

3 0

Answer:

Step-by-step explanation:

$y^{2} = r^{2} + (4,2)^{2} \\\\ y^{2} - r^{2} = (4,2)^{2} y^{2} = r^{2} + z^{2} \\\\ y^{2} - r^{2} = z^{2}\\so: z^{2} = (4,2)^{2} ----> z = 4,2$

You might be interested in

Evaluate f(7) *<br> f (x) = –2x² + 4

Firdavs [7]

Input 7 for every x so
f(7) = -2 (7)^2 +4
f(7) = -2(49) +4
f(7) = -98 +4
f(7) = -94

6 0

3 years ago

Read 2 more answers

Simplify the expression:<br> 5(-1 + x) =

mamaluj [8]

Answer:

5x-5

Step-by-step explanation:

hope this helped!

6 0

3 years ago

Read 2 more answers

A skull cleaning factory cleans animal skulls of deer, buffalo and other types of animals using flesh-eating beetles. the fact

Shtirlitz [24]

The solution for this problem is:
The population is 500 times bigger since 8000/24 = 500. The population after t days is computed by:P(t) = P₀·4^(t/49)
Solve for t: 8000 = 8·4^(t/49) 1000 = 4^(t/49) log₄(1000) = t/49t = 49log₄(1000) ≅ 244 days

8 0

3 years ago

I need all the work shown ..help

zhannawk [14.2K]

You slowly go down the bottom row and multiply each digit by the top row.

8 0

3 years ago

..................................

yanalaym [24]

Answer:

The answer is a² .

Step-by-step explanation:

You have to substitute x and y into the expression :

$let \: x = a \cos(θ) \\ let \: y = a \sin( θ)$

${x}^{2} + {y}^{2} = {(a \cosθ )}^{2} + {(a \sinθ) }^{2}$

${x}^{2} + {y}^{2} = {a}^{2}( {cos}^{2}θ) + {a}^{2} ({sin}^{2}θ)$

Next, you have to apply Basic Trigonometric Identity :

${sin}^{2} θ + {cos}^{2} θ = 1$

${x}^{2} + {y}^{2} = {a}^{2} ( {cos}^{2} θ + {sin}^{2} θ)$

${x}^{2} + {y}^{2} = {a}^{2} (1)$

${x}^{2} + {y}^{2} = { a}^{2}$

8 0

3 years ago