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NeTakaya
3 years ago
12

MK and ML are tangent to circle J. If MK = 6x – 15 and ML = 2x + 9, find x. * am i right?? * --> provide details if i'm wrong

.

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
3 0

Answer:

Step-by-step explanation:

y^{2} = r^{2}  + (4,2)^{2} \\\\ y^{2} - r^{2} = (4,2)^{2} y^{2} =  r^{2} + z^{2} \\\\ y^{2} - r^{2} = z^{2}\\so: z^{2} = (4,2)^{2}  ----> z = 4,2

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How do you calculate the area and the perimeter of a parallelogram and a triangle?
Mnenie [13.5K]

for parallelograms:

area = b(h)

so basically, the length times the height. just like how you would find the area of a square.

perimeter: just add all of the sides together.

for triangles:

area = 1/2(b) x h

so half the length multiplied by the height. for example, if the length was 4, you have to use half of that. so that means 2 times whatever the height is.

perimeter: again, just add all three sides together

7 0
3 years ago
Read 2 more answers
Plsss helppp I’m dying!! —> Complete the square to determine if the equation is a circle, quadratic equation, or other
sashaice [31]

a) The equation represents an ellipse.

b) The equation represents a circle.

c) The equation represents a parabola.

<h3>How to infer the graphical form of a general equation</h3>

In this problem we have <em>general</em> equations of the form A · x² + B · y² + C · x + D · y + E = 0, which have to be modified into <em>standard</em> form to infer its <em>graphical</em> form. This procedure can be done by <em>algebra</em> properties:

16 · x² + 4 · y² + 96 · x - 8 · y + 84 = 0

[(4 · x)² + 2 · 12 · (4 · x)] + [(2 · y)² - 2 · 2 · (2 · y)] = - 84

[(4 · x)² + 2 · 12 · (4 · x) + 144] + [(2 · y)² - 2 · 2 · (2 · y) + 4] = 64

(4 · x + 12)² + (2 · y + 2)² = 64

4² · (x + 3)² + 2² · (y + 2)² = 64

(x + 3)² / 4 + (y + 2)² / 16 = 1 : Ellipse

x² + y² + 8 · x - 6 · y - 15 = 0

(x² + 8 · x) + (y² - 6 · y) = 15

(x² + 2 · 4 · x + 16) + (y² - 2 · 3 · y + 9) = 40

(x + 4)² + (y - 3)² = 40 : Circle

x² + 6 · x + 4 · y + 5 = 0

x² + 6 · x + 5 = - 4 · y

y = - (1 / 4) · x² - (3 / 2) · x - (5 / 4) : Parabola

To learn more on ellipses: brainly.com/question/19507943

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4 0
1 year ago
A rectangular pyramid has a volume of 160 cubic feet. Find two possible sets of measurements for the base area and height of the
muminat

\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh~~ \begin{cases} B=area~of\\ \qquad its~base\\ h=height\\ \cline{1-1} V=160 \end{cases}\implies 160=\cfrac{Bh}{3}\implies 480=Bh \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} 480=&2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 3\cdot 5\\ &8\cdot 60\\ &32\cdot 15 \end{cases}~\hspace{5em}\stackrel{B}{8}\times\stackrel{h}{60}\qquad \qquad \stackrel{B}{32}\times\stackrel{h}{15}

4 0
3 years ago
How do you simplify 875/1000
OverLord2011 [107]
Find\ GCF(875;\ 1000)

875|5\\175|5\\.\ 35|5\\.\ \ 7|7\\.\ \ 1|\\875=\fbox5\times\fbox5\times\fbox5\times7\\\\1000|5\\.\ 200|5\\.\ \ 40|5\\.\ \ \ 8|2\\.\ \ \ 4|2\\.\ \ \ 2|2\\.\ \ \ 1|\\1000=\fbox5\times\fbox5\times\fbox5\times2\times2\times2

GCF(875;\ 1000)=\fbox5\times\fbox5\times\fbox5=125\\\\\frac{875}{1000}=\frac{875:125}{1000:125}=\frac{7}{2\times2\times2}=\boxed{\frac{7}{8}}
8 0
3 years ago
The numbers 2-12 are written on cards and placed in the bag.what is the probability of picking an even number then replacing it
weeeeeb [17]

2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12

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6 cards contain even numbers.

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Answer: p(even then 7) = 6/121

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