Can you please help me solve this?

Find the values of the six trigonometric functions of an angle in standard position if the point with coordinates (12,5) lies on

anastassius [24]

Find the values of the six t

6 0

3 years ago

This subject is hard enough why they have to make it harderrrrrrr-

Citrus2011 [14]

Fr mathhhhhhhhhHhHhHhhHhhHhHhhHhHHhH

5 0

3 years ago

Read 2 more answers

Just question 1, please.

ANTONII [103]

Step-by-step explanation:

We can start by writing an equation to describe the data set. For 2D data, one equation form we can use is y=m*x + b, where x is the input and y is the output. Since yuan are put in and dollars are put out, x represents yuan and y represents dollars in this instance.

To find the equation, we can start by plugging in two points, such as (50, 1.25) and (100, 7.5). The slope, or m, is equal to the change in y/change in x, or

(7.5-1.25)/(100-50) = 6.25/50

= 0.125. This means that for each yuan put in, 0.125 dollars come out, according to the formula.

Next, we must find b. Plugging 0.125 in for m and taking a set of points, such as (50, 1.25), we get

1.25 = 50(0.125) + b

1.25 = 6.25 + b

subtract both sides by 6.25 to isolate the b

-5 = b

Therefore, we can write our equation as

y = 0.125 * x - 5

In this equation, there is an exchange rate of 0.125, meaning that for each yuan put in, 0.125 dollars are coming out. The -5 symbolizes that for each transaction, 5 yuan are being lost, which is the fee for exchanging money.

To check if the equation works, we can try it for options such as (200, 20) and (250, 26.25). This does work, so we can move forward with our equation.

For (c), our equation is y = 0.125 * x - 5, with the y representing dollars, x representing yuan, 0.125 representing the exchange rate, and -5 representing the fee for exchaning mone

For (b), because 5 yuan are subtracted from the exchange rate for each transaction, it is fair to assume that there is a fee for exchanging money. There is a fee of 5 yuan per transaction. In dollars, using the exchange rate of 0.125 dollars per yuan, this is equal to 0.625 dollars

For (a), the exchange rate is 0.125 dollars per yuan. We know this because for each yuan put in, 0.125 dollars are coming out after taking into account the fee

6 0

3 years ago

When I'm 64

NemiM [27]

Chucks age=C
Dave’s age=x

C=x-3

6 0

3 years ago

Name/ Uid:1. In this problem, try to write the equations of the given surface in the specified coordinates.(a) Write an equation

Gemiola [76]

To find:

(a) Equation for the sphere of radius 5 centered at the origin in cylindrical coordinates

(b) Equation for a cylinder of radius 1 centered at the origin and running parallel to the z-axis in spherical coordinates

Solution:

(a) The equation of a sphere with center at (a, b, c) & having a radius 'p' is given in cartesian coordinates as:

$(x-a)^{2}+(y-b)^{2}+(z-c)^{2}=p^{2}$

Here, it is given that the center of the sphere is at origin, i.e., at (0,0,0) & radius of the sphere is 5. That is, here we have,

$a=b=c=0,p=5$

That is, the equation of the sphere in cartesian coordinates is,

$(x-0)^{2}+(y-0)^{2}+(z-0)^{2}=5^{2}$

$\Rightarrow x^{2}+y^{2}+z^{2}=25$

Now, the cylindrical coordinate system is represented by $(r, \theta,z)$

The relation between cartesian and cylindrical coordinates is given by,

$x=rcos\theta,y=rsin\theta,z=z$

$r^{2}=x^{2}+y^{2},tan\theta=\frac{y}{x},z=z$

Thus, the obtained equation of the sphere in cartesian coordinates can be rewritten in cylindrical coordinates as,

$r^{2}+z^{2}=25$

This is the required equation of the given sphere in cylindrical coordinates.

(b) A cylinder is defined by the circle that gives the top and bottom faces or alternatively, the cross section, & it's axis. A cylinder running parallel to the z-axis has an axis that is parallel to the z-axis. The equation of such a cylinder is given by the equation of the circle of cross-section with the assumption that a point in 3 dimension lying on the cylinder has 'x' & 'y' values satisfying the equation of the circle & that 'z' can be any value.

That is, in cartesian coordinates, the equation of a cylinder running parallel to the z-axis having radius 'p' with center at (a, b) is given by,

$(x-a)^{2}+(y-b)^{2}=p^{2}$

Here, it is given that the center is at origin & radius is 1. That is, here, we have, $a=b=0,p=1$ . Then the equation of the cylinder in cartesian coordinates is,

$x^{2}+y^{2}=1$

Now, the spherical coordinate system is represented by $(\rho,\theta,\phi)$

The relation between cartesian and spherical coordinates is given by,

$x=\rho sin\phi cos\theta,y=\rho sin\phi sin\theta, z= \rho cos\phi$

Thus, the equation of the cylinder can be rewritten in spherical coordinates as,

$(\rho sin\phi cos\theta)^{2}+(\rho sin\phi sin\theta)^{2}=1$

$\Rightarrow \rho^{2} sin^{2}\phi cos^{2}\theta+\rho^{2} sin^{2}\phi sin^{2}\theta=1$

$\Rightarrow \rho^{2} sin^{2}\phi (cos^{2}\theta+sin^{2}\theta)=1$

$\Rightarrow \rho^{2} sin^{2}\phi=1$ (As $sin^{2}\theta+cos^{2}\theta=1$ )

Note that $\rho$ represents the distance of a point from the origin, which is always positive. $\phi$ represents the angle made by the line segment joining the point with z-axis. The range of $\phi$ is given as $0\leq \phi\leq \pi$ . We know that in this range the sine function is positive. Thus, we can say that $sin\phi$ is always positive.

Thus, we can square root both sides and only consider the positive root as,

$\Rightarrow \rho sin\phi=1$

This is the required equation of the cylinder in spherical coordinates.

Final answer:

(a) The equation of the given sphere in cylindrical coordinates is $r^{2}+z^{2}=25$

(b) The equation of the given cylinder in spherical coordinates is $\rho sin\phi=1$

7 0

3 years ago