You would solve it by multiplying the sides of the triangle
1: 64
2: 59
3: 49
A triangle should always add up to 180 degrees. So just add up the angles you have and subtract them from 180
Answer:
can u give more information than i will answer
Step-by-step explanation:
Answer:
= 4√53 units
that is option(a)
Step-by-step explanation:
all sides of the square are of the same length
so if we get the length if this side, we can calculate its perimeter
there's this formula,
<u>side length between two points, let's say A(x, y) and B(p, q), is equal to </u>
![\mathsf{ \sqrt{ {(x - p)}^{2} + {(y - q)}^{2} } }](https://tex.z-dn.net/?f=%20%5Cmathsf%7B%20%5Csqrt%7B%20%7B%28x%20-%20p%29%7D%5E%7B2%7D%20%2B%20%20%7B%28y%20-%20q%29%7D%5E%7B2%7D%20%20%7D%20%7D)
so here we go,
the same points A and B here are
(4, 7) and (-3, 5)
therefore, side length :-
![= \mathsf{ \sqrt{( {7 - 5})^{2} + {(4 - ( - 3))}^{2} } }](https://tex.z-dn.net/?f=%20%20%3D%20%5Cmathsf%7B%20%5Csqrt%7B%28%20%7B7%20-%205%7D%29%5E%7B2%7D%20%20%2B%20%20%7B%284%20-%20%28%20-%203%29%29%7D%5E%7B2%7D%20%7D%20%7D%20)
![= \mathsf{ \sqrt{ {2}^{2} + {7}^{2} } }](https://tex.z-dn.net/?f=%20%3D%20%20%5Cmathsf%7B%20%5Csqrt%7B%20%7B2%7D%5E%7B2%7D%20%2B%20%20%7B7%7D%5E%7B2%7D%20%20%7D%20%7D%20)
![= \mathsf{ \sqrt{4 + 49} }](https://tex.z-dn.net/?f=%20%3D%20%20%5Cmathsf%7B%20%20%5Csqrt%7B4%20%2B%2049%7D%20%20%7D%20)
![= \mathsf{\sqrt{53} }](https://tex.z-dn.net/?f=%20%3D%20%20%20%5Cmathsf%7B%5Csqrt%7B53%7D%20%7D)
the side length comes out to be <u>√(</u><u>53</u><u>) </u>
now perimeter of a square is
4 × side length
= 4√53 units