X= number of student tickets
Y= number of on student tickets
x+y=311
0.50x + 1.50y = 385.50
Solve x in 1st equation
X+y=311
X= -y + 311
Now substitute x into second equation to solve for y
0.50(-y+311)+ 1.50y = 385.50
-0.50y+311.50+1.50y=385.50
Y+311.50=385.50
Y= 385.50-311.50
Y= 74
Now substitute y answer to first equation to find x
X+y=311
X+ 74=311
X= 311-74
X= 237
So 237 students tickets and 74 non students tickets
Answer:
0.25 rad to the nearest hundredth radian
Step-by-step explanation:
Here is the complete question
Suppose a projectile is fired from a cannon with velocity vo and angle of elevation (theta). The horizontal distance R(θ) it travels (in feet) is given by the following.
R(θ) = v₀²sin2θ/32
If vo=80ft/s what angel (theta) (in radians) should be used to hit a target on the ground 95 feet in front of the cannon?
Do not round any intermediate computations, and round your answer(s) to the nearest hundredth of a radian.
(θ)= ?rad
Solution
R(θ) = v₀²sin2θ/32
If v₀ = 80 ft/s and R(θ) = 95 ft
θ = [sin⁻¹(32R(θ)/v₀²)]/2
= [sin⁻¹(32 × 95/80²)]/2
= [sin⁻¹(3040/6400)]/2
= [sin⁻¹(0.475)]/2
= 28.36°/2
= 14.18°
Converting 14.18° to radians, we have 14.18° × π/180° = 0.2475 rad
= 0.25 rad to the nearest hundredth radian
Answer: 3j +4
3(j)+ 3(2) = 3j+ 6 - 2 = 3j +4
Hope this helps
Answer:
f(-2) = -3
Explanation:
Not sure if those last couple numbers are answer choices, but I'm going to infer that they might be.
Twenty four over the quantity of 3 x minus two in standard form is:
f(x) = <span>24<span>3x−2</span></span>
Since the number in the ( ) = x, plug in for x using f(-2)
<span>24<span>3∗<span>(−2)</span>−2</span></span>
P E {M D} {A S} for where to solve first
Multiply the 3 and (-2):
<span>24<span>−6−2</span></span>
Add -6 and -2:
<span>24<span>−8</span></span>
Divide the rest:
f(-2) = -3
X=-1 is the answer. Hope that helps!
