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3 years ago

What k-1/3=5/6 equal ?

1 answer:

7 0

The value of "K"

$k -\frac{1}{3} = \frac{5}{6}$

MMC (3,6)
3,6 | 3
1,2 | 2
1,1 |__ 3*2 = 6

Solving:
$k -\frac{1}{3} = \frac{5}{6}$
$\frac{6k}{6} - \frac{2}{6} = \frac{5}{6}$
cancel denominators (6)
$6k - 2 = 5$
$6k = 5+2$
$6k = 7$
$\boxed{k = \frac{7}{6} }$

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Answer:

Option D - Stretched by a factor of 2, reflected over the y-axis, and translated 9 units left.

Step-by-step explanation:

Given : The function $y=\sqrt{-4x-36}$

To find : Which of the following describes the graph of $y=\sqrt{-4x-36}$ compared to the parent square root function?

Solution :

First we simplify the given expression

$y=\sqrt{-4x-36}$

$y=\sqrt{4(-x-9)}$

$y=2\sqrt{-(x+9)}$

→When we see the original square root function minus was taken outside x and 9 was added from x and 2 was multiplied to the entire function.

Multiplying 2 in the function will give you the stretched by a factor of 2.

$g(x)=\sqrt{-x}$ shows the reflection about y-axis i.e, (x,y)→(-x,y).

If f(x)→f(x+b) then function is shifted left by unit b

⇒ g(x))→g(x+9) then function is shifted left by unit 9

Therefore, The graph of was stretched by a factor of 2, reflected over the y-axis, and translated 9 units left to obtain the graph of the function .

So, Option D is correct.

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3 years ago

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Using the completing-the-square method, rewrite f(x) = x2 − 6x + 2 in vertex form.

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Answer:

f(x)=(x-3)^2-7

Step-by-step explanation:

Vertex form: f(x) = a(x-h)^2+k

x^2-6x+9+2=f(x)+9

(x-3)^2+2=f(x)+9

f(x)=(x-3)^2-7

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Answer:

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Step-by-step explanation:

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A = 2π(3²) . . . . . . matches a term in the last choice

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A = 2πrh

For the given radius and height, the lateral area in square centimeters is ...

A = 2π(3)(14) . . . . . . matches a term in the last choice

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<em>Comment on answer choices</em>

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Answer:

single term
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Step-by-step explanation:

1. 3x

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This is a sum of 4 terms, some of which can be expanded:

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