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3 years ago

If McDonald sells 5 cows for $100 each and buys a horse for $250 how much would he have

Mathematics

2 answers:

Bumek [7]3 years ago

8 0

100x5= $500
500-250= $250

Radda [10]3 years ago

3 0

Answer: 250

Step-by-step explanation:

5(1000)=500

500-250= 250

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What additional piece of information is needed to show that DEF = PQR by ASA? E F R. line DF=line PR FER ZDELP Oline EF=line QR

Rina8888 [55]

Answer:

Given: PR=EF, QR=DE and PQ=FD

Now, In △PRQ and △DEF

PR=EF

QR=DE

PQ=FD

Thus, △PQR≅△FDE (SSS rule).

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3 years ago

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In the equation y= -2x -3 over 5, identify the slope, the y-intercept, and whether the line is rising, falling, horizontal, or v

Hoochie [10]

Answer:

Slope = -2

y-intercept = -3/5

Falling

Step-by-step explanation:

$y= -2x - \frac{3}{5} \\ y = mx + b$

m = Slope = -2

y-intercept = b =

$- \frac{3}{5}$

The slope of the equation has a negative number so the graph is falling

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4 years ago

Solve the formula<br> -4x+y= -6 for x.

Arte-miy333 [17]

Answer:

x = 3/2 + y/4

Step-by-step explanation:

5 0

3 years ago

Step 2: Radii OK and NL are perpendicular to OM because of the radius-tangent theorem. By definition of perpendicular, angles KO

solong [7]

Answer:

Angle Angle Angle (AAA) property

Step-by-step explanation:

A right angled triangle is a triangle that has one of its angles to equal $90^{0}$ . It could be in the form of an isosceles triangle or an acute angled triangle.

The given question compares the congruence properties of two triangles, KOM and LNM.

Thus,

<KOM = <LNM (right angle theorem)

<LMN = <KMO (common angles to both triangles)

⇒ <OKM = <NLM (property of a triangle i.e sum of angle in a triangle is $180^{0}$ )

ΔKOM = ΔLNM (congruence property)

Therefore, by angle angle angle (AAA) congruence property, the two triangles are similar.

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4 years ago

A selective university advertises that 96% of its bachelor’s degree graduates have, on graduation day, a professional job offer

OLEGan [10]

Answer:

The probability is $P( p < 0.9207) = 0.0012556$

Step-by-step explanation:

From the question we are told

The population proportion is $p = 0.96$

The sample size is $n = 227$

The number of graduate who had job is k = 209

Generally given that the sample size is large enough (i.e n > 30) then the mean of this sampling distribution is

$\mu_x = p = 0.96$

Generally the standard deviation of this sampling distribution is

$\sigma = \sqrt{\frac{p (1 - p )}{n} }$

=> $\sigma = \sqrt{\frac{0.96 (1 - 0.96 )}{227} }$

=> $\sigma = 0.0130$

Generally the sample proportion is mathematically represented as

$\^ p = \frac{k}{n}$

=> $\^ p = \frac{209}{227}$

=> $\^ p = 0.9207$

Generally probability of obtaining a sample proportion as low as or lower than this, if the university’s claim is true, is mathematically represented as

$P( p < 0.9207) = P( \frac{\^ p - p }{\sigma } < \frac{0.9207 - 0.96}{0.0130 } )$

$\frac{\^ p - p}{\sigma } = Z (The \ standardized \ value\ of \ \^ p )$

$P( p < 0.9207) = P(Z< -3.022 )$

From the z table the area under the normal curve to the left corresponding to -3.022 is

$P(Z< -3.022 ) = 0.0012556$

=> $P( p < 0.9207) = 0.0012556$

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3 years ago