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GarryVolchara [31]
3 years ago
9

There were 10 bunches of roses and tulips. Each bunch had 5 of the same flowers. There were 2 more bunches of tulips than roses.

How many tulips were there?
Mathematics
1 answer:
____ [38]3 years ago
6 0

Answer:

7

Step-by-step explanation:

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The answer is C. All calculations of a cone or the cone equal up to 353.77. Hope this helps!
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An article suggested that yield strength (ksi) for A36 grade steel is normally distributed with μ = 42 and σ = 5.5.
alexandr1967 [171]

Answer:

a)P( X

We want this probability:

P( X >64)

And using the z score formula given by:

z = \frac{x -\mu}{\sigma}

We got:

P( X >64) =P(Z> \frac{64-42}{5.5}) =P(Z>4)=0.0000316

b) For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.25   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.75 of the area on the left and 0.25 of the area on the right it's z=0.674. On this case P(Z<0.674)=0.75 and P(z>0.674)=0.25

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=0.674

And if we solve for a we got

a=42 +0.674*5.5=45.707

So the value of height that separates the bottom 75% of data from the top 25% is 45.707.  

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(42,25.5)  

Where \mu=42 and \sigma=5.5

And we want this probability:

P( X

And using the z score formula given by:

z = \frac{x -\mu}{\sigma}

We got:

P( X

We want this probability:

P( X >64)

And using the z score formula given by:

z = \frac{x -\mu}{\sigma}

We got:

P( X >64) =P(Z> \frac{64-42}{5.5}) =P(Z>4)=0.0000316

Part b

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.25   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.75 of the area on the left and 0.25 of the area on the right it's z=0.674. On this case P(Z<0.674)=0.75 and P(z>0.674)=0.25

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=0.674

And if we solve for a we got

a=42 +0.674*5.5=45.707

So the value of height that separates the bottom 75% of data from the top 25% is 45.707.  

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Everything has been explained in there

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3 years ago
Determine which of the following equations, when graphed, intersect at the point (4, 0).
dexar [7]

Answer:

x - y = 4

x + y = 4

Step-by-step explanation:

Substitute x=4 and y=0 in every equation. If both sides of the equal sign are equal, (LS=RS, left side equals right side) then the graph intersects at (4,0).

- x - y = 4

- (4) - 0 = 4

-4 = 4

LS≠RS

x - y = 4

4 - 0 = 4

4 = 4

LS=RS

2 x + y = 7

2(4) + 0 = 7

8 = 7

LS≠RS

2 x + y = -7

2(4) + 0 = -7

8 = -7

LS≠RS

x + y = 4

4 + 0 = 4

4 = 4

LS=RS

2 x - y = 7

2(4) - 0 = 7

8 - 0 = 7

8 = 7

LS≠RS

Only x - y = 4  and x + y = 4  intersect at (4, 0).

4 0
3 years ago
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