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mojhsa [17]
2 years ago
14

1/6 divided by 6 by 6

Mathematics
2 answers:
Ahat [919]2 years ago
7 0

the answer is 1/216

hope this might of helped :/

Alex_Xolod [135]2 years ago
3 0
The answer would be 1/216.
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The angle of elevation from me to the top of a hill is 51 degrees. The angle of elevation from me to the top of a tree is 57 deg
julia-pushkina [17]

Answer:

Approximately 101\; \rm ft (assuming that the height of the base of the hill is the same as that of the observer.)

Step-by-step explanation:

Refer to the diagram attached.

  • Let \rm O denote the observer.
  • Let \rm A denote the top of the tree.
  • Let \rm R denote the base of the tree.
  • Let \rm B denote the point where line \rm AR (a vertical line) and the horizontal line going through \rm O meets. \angle \rm B\hat{A}R = 90^\circ.

Angles:

  • Angle of elevation of the base of the tree as it appears to the observer: \angle \rm B\hat{O}R = 51^\circ.
  • Angle of elevation of the top of the tree as it appears to the observer: \angle \rm B\hat{O}A = 57^\circ.

Let the length of segment \rm BR (vertical distance between the base of the tree and the base of the hill) be x\; \rm ft.

The question is asking for the length of segment \rm AB. Notice that the length of this segment is \mathrm{AB} = (x + 20)\; \rm ft.

The length of segment \rm OB could be represented in two ways:

  • In right triangle \rm \triangle OBR as the side adjacent to \angle \rm B\hat{O}R = 51^\circ.
  • In right triangle \rm \triangle OBA as the side adjacent to \angle \rm B\hat{O}A = 57^\circ.

For example, in right triangle \rm \triangle OBR, the length of the side opposite to \angle \rm B\hat{O}R = 51^\circ is segment \rm BR. The length of that segment is x\; \rm ft.

\begin{aligned}\tan{\left(\angle\mathrm{B\hat{O}R}\right)} = \frac{\,\rm {BR}\,}{\,\rm {OB}\,} \; \genfrac{}{}{0em}{}{\leftarrow \text{opposite}}{\leftarrow \text{adjacent}}\end{aligned}.

Rearrange to find an expression for the length of \rm OB (in \rm ft) in terms of x:

\begin{aligned}\mathrm{OB} &= \frac{\mathrm{BR}}{\tan{\left(\angle\mathrm{B\hat{O}R}\right)}} \\ &= \frac{x}{\tan\left(51^\circ\right)}\approx 0.810\, x\end{aligned}.

Similarly, in right triangle \rm \triangle OBA:

\begin{aligned}\mathrm{OB} &= \frac{\mathrm{AB}}{\tan{\left(\angle\mathrm{B\hat{O}A}\right)}} \\ &= \frac{x + 20}{\tan\left(57^\circ\right)}\approx 0.649\, (x + 20)\end{aligned}.

Equate the right-hand side of these two equations:

0.810\, x \approx 0.649\, (x + 20).

Solve for x:

x \approx 81\; \rm ft.

Hence, the height of the top of this tree relative to the base of the hill would be (x + 20)\; {\rm ft}\approx 101\; \rm ft.

6 0
3 years ago
Area of 16+8×+×^2meters. What is the side length
wolverine [178]

Answer:

  x +4

Step-by-step explanation:

The trinomial x² +8x +16 is a perfect square trinomial, so factors as ...

  x² +8x +16 = (x +4)²

Assuming the side length is one of the factors of the given area, it will be ...

  side length = (x +4)

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3 years ago
1. Write down the solution set for each system with variables x, y, and z. zi cexo
insens350 [35]

Answer: need point so HA!

Step-by-step explanation:

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2 years ago
Suppose f(x) = 12x – 1,400 and g(x) = 12x – 1,535. Describe the transformation of the graph of f to the graph of g. Group of ans
m_a_m_a [10]
The graph is translates down 135 units, because you can see how the y-intercept decreased by 135 units from f(x) to g(x).
3 0
3 years ago
1. Which ratios form a proportion? a. 4/9, 12 / 25 b. 3 / 7, 18 / 42 c. 5/11, 20/45 d. 5/8, 15/25. 2. Which ratio forms a propor
harkovskaia [24]
I am pretty sure that the right answer for the first question which is being asked is the second option - <span><span>b. 3 / 7, 18 / 42
</span>What about the next one, I bet it's </span> d. 60 / 100. 3
And the last one is  a. 5/8=15/24 
4 0
3 years ago
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