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mojhsa [17]
2 years ago
14

1/6 divided by 6 by 6

Mathematics
2 answers:
Ahat [919]2 years ago
7 0

the answer is 1/216

hope this might of helped :/

Alex_Xolod [135]2 years ago
3 0
The answer would be 1/216.
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-10ab+2ab^2-9ab+7 what is the simplest form
vesna_86 [32]

Answer:

-19ab + 2ab^2 +7

Step-by-step explanation:

all you do is combine the like terms. and the omly like terms are -10ab and -9ab. 2ab^2 is not one of the like terms simply because of that ^2.

3 0
3 years ago
PLEASE SOMEONE HELP ME PLEASE :(
creativ13 [48]

Answer:

1 and 5= corresponding angles.

4 and 2=vertical opposite angle

3 and 6=co interior angle.

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5 and 3= alternate interior angle

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3 0
3 years ago
Read 2 more answers
So i need help with this question
lawyer [7]

Answer:

multiply both sides by 8

Step-by-step explanation:

I don't really know why I just know lol hope this helps

8 0
2 years ago
A map is drawn using a scale of 80 mi to 1 cm. On the map , the two cities are 7.5 cm apart. What is the actual distance between
meriva
We know that
scale =measure in the map/measure in the actual
measure in the actual=measure in the map/scale
scale=1 cm/ 80 mi
for
measure in the map=7.5 cm
measure in the actual=?
measure in the actual=7.5 /(1/80)-----> 7.5*80-----> 600 mi

the answer is
<span>the actual distance between the two cities is 600 miles</span>
6 0
2 years ago
Verify the following trigonometric identity: (csc x + cot x)^2 = cos x +1/ 1- cos x
Airida [17]

9514 1404 393

Explanation:

As written, the equation is not an identity. Perhaps you want to show ...

  (csc(x) +cot(x))² = (cos(x) +1)/(1 -cos(x))

__

We will transform the left-side expression to the form of the right-side expression.

  (\csc(x)+\cot(x))^2=\left(\dfrac{1}{\sin(x)}+\dfrac{\cos(x)}{\sin(x)}\right)^2=\dfrac{(1+\cos(x))^2}{\sin(x)^2}\\\\=\dfrac{(1+\cos(x))^2}{1-\cos(x)^2}=\dfrac{1+\cos(x)}{1-\cos(x)}\cdot\dfrac{1+\cos(x)}{1+\cos(x)}=\boxed{\dfrac{\cos(x)+1}{1-\cos(x)}}

3 0
3 years ago
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