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disa [49]
3 years ago
14

The area of a rectangle is 27 m^2 , and the length of the rectangle is 3 m less than twice the width. Find the dimensions of the

rectangle.
Length: ___m
Width: ____m
Mathematics
1 answer:
vagabundo [1.1K]3 years ago
3 0
Let L be the length of the rectangle and W be the width. In the problem it is given that L=2W-3. It is also given that the area LW=27. Substituting in the length in terms of width, we have W(2W-3)=27 \\ 2W^2-3W-27=0 \\ (2W-9)(W+3)=0. Using the zero product property, 2W-9=0 \text{ or } W+3=0. Solving these we get the width W=4.5 \text{ or } -3. However, it doesn't make sense for the width to be negative, so the width must be \boxed{4.5 \text{ m}}. From that we can tell the length L=2(4.5)-3=\boxed{6 \text{ m}}. 
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