Answer:
the rate of each train is 139 km/h and 159 km/h.
Step-by-step explanation:
let
v = the rate of the slower train
v + 20 = the rate of the faster train
d = 1490 km the distance that the two train will travel
t = 5 hr the time of the travel
since speed = distance/time => distance = speed*time
v*t + (v+20)t = d
5v + 5(v + 20) = 1490
5v+5(v+20)=1490
Step 1: Simplify both sides of the equation.
5v+5(v+20)=1490
5v+(5)(v)+(5)(20)=1490(Distribute)
5v+5v+100=1490
(5v+5v)+(100)=1490(Combine Like Terms)
10v+100=1490
10v+100=1490
Step 2: Subtract 100 from both sides.
10v+100−100=1490−100
10v=1390
Step 3: Divide both sides by 10.
10v/10 = 1390/10
v = 139km/h
Next
we add 139 to 20
139 + 20 = 159 km/h
the rate of each train is 139 km/h and 159 km/h.
All real numbers so the answer is D
Step-by-step explanation:
So the answer for 33+45+78 is 156.
If you want to check that, you can use inverse operations, so subtract.
156-78=78. (Check 78)
78-45=33 (Check 45 and 33)
Well, now it's checked because we used all the factors of the equation!
Es la b 1DM 5c 6d 0U
4.350+2.710+3.500= 10.560
Nacieron 10.560 productos en la huerta.
$530.40/4= $132.60
$132.60 x 3=$397.80
Or
$530.40 x .75= $397.80
