Simplify both sides of the equation
(20)(4)= 4(5x+1)
Simplify
80 = 20x+4
Flip the equation
20x+4 = 80
Subtract 4 from both sides
20x+4-4 = 80-4
20x = 76
Divide both sides by 20
20x/20 = 76/20
x= 3.8
There is one solution in this equation
Answer:
1). infer 2). fired 3). filed 4). filer 5). elfin 6). nerdy 7). felid 8). finer 9). liner 10). lined 11). fiery 12). fiend 13). ferly 14). ferny 15). lindy 16). fined 17). lifer 18). field 19). redly 20). riley 21). riled 22). liney 23). rifle 24). drily 25). fried 26). diner 27). flier 28). flied 29). idler 30). deify 31). reify 32). yield 33). refly 34). dynel 35). edify 36). flyer
hope this helps :)
Answer:
109.2-23.6 = 85.6
Step-by-step explanation:
use bodmas
B=bracket
O=of or multiplication
D=division
M=multiplication
A=addition
S=subtraction
so when you are opening a bracket you multipli the number in the bracket with the one outside the bracket
I.E
4×27.3=109.3
4×5.9=23.6
109-23.6=85.6
Let X = science homework.
Then math homework would be 3x ( three times as long).
Now you have math plus science = 64 minutes:
x + 3x = 64
Combine like terms:
4x = 64
Divide both sides by 4:
x = 64 / 4
x = 16
He spent 16 minutes on science and 48 minutes on math.
If the value of the z-score is 1. Then the probability that a cat will weigh less than 11 pounds will be 0.84134.
<h3>What is the z-score?</h3>
The z-score is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.
The z-score is given as
z = (x - μ) / σ
Where μ is the mean, σ is the standard deviation, and x is the sample.
The weight of a cat is normally distributed with a mean of 9 pounds and a standard deviation of 2 pounds.
Then the probability that a cat will weigh less than 11 pounds will be
The value of z-score will be
z = (11 – 9) / 2
z = 1
Then the probability will be
P(x < 11) = P(z < 1)
P(x < 11) = 0.84134
Thus, the probability that a cat will weigh less than 11 pounds will be 0.84134.
More about the z-score link is given below.
brainly.com/question/15016913
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