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koban [17]
3 years ago
14

Figure 1 is dilated to get Figure 2. What is the scale factor? Enter your answer, as a fraction in simplified form, in the box.

​ $\text{Basic}$ $x$$y$$x^2$$\sqrt{ }$$\frac{x}{ }$ $x\frac{ }{ }$ $x^{ }$$x_{ }$$\degree$$\left(\right)$$\abs{ }$$\pi$$\infty$ Two triangles, one with a short leg measured at 24 labeled figure 1 and one with short leg measured at 8 labeled figure 2.
Mathematics
2 answers:
klemol [59]3 years ago
7 0

Answer:

1/2 is the correct answer.

sveta [45]3 years ago
5 0

Answer:

1/2

Step-by-step explanation:

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H + 3 = -13 <br> please show work
cricket20 [7]

H= -16

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Which statement about the zeros of the graphed function is true?
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A. The function has three distinct real zeros.

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Which of these triangles appears not to be congruent to any others shown
Wittaler [7]

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B, C, F

Step-by-step explanation:

B- has different lengths for each side and different angles

C-has different lengths for each side and different angles

F-has different lengths for each side and different angles

Non congruent triangles means if shape is reflected or rotated they would not look the same. Congruent triangles have same equal length and angles are equal in measure.

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3 years ago
You are required to choose two topics from a list of five to write about on your science test. How many different pairings are p
marissa [1.9K]
A B C D E represent the subjects


A+A1

A+B2

A+C3

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B+B6

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7 0
3 years ago
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PLEASE HELP ME!!
Ludmilka [50]

Answer:

<h2>The population will reach 1200 after about 2.8 years</h2>

Step-by-step explanation:

The question is incomplete. Here is the complete question.

The population of a certain species of bird in a region after t years can be modeled by the function P(t) = 1620/ 1+1.15e-0.42t , where t ≥ 0. When will the population reach 1,200?

According to question we are to calculate the time t that the population P(t) will reach 1200.To do this we will substitute P(t) = 1,200 into the equation and calculate for the time 't'.

Given;

P(t) = \frac{1620}{1+1.15e^{-0.42t} } \\\\at \ P(t)= 1200;\\\\1200 =  \frac{1620}{1+1.15e^{-0.42t} }\\\\cross\ multiplying\\\\1+1.15e^{-0.42t} = \frac{1620}{1200} \\\\1+1.15e^{-0.42t}  = 1.35\\\\1.15e^{-0.42t} = 1.35-1\\\\e^{-0.42t} = \frac{0.35}{1.15}\\ \\e^{-0.42t}  = 0.3043\\\\Taking \ ln\ of\ both\ sides\\\\lne^{-0.42t}  = ln0.3043\\\\-0.42t = -1.1897\\\\t = \frac{-1.1897}{-0.42} \\\\t = 2.8 years\\\\

The population will reach 1200 after about 2.8 years

6 0
3 years ago
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