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3 years ago

¿Cómo es esto?, Plisssssssssss ayuda

Mathematics

1 answer:

mel-nik [20]3 years ago

6 0

Answer

I think it is number 5

Step-by-step explanation:

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The area of a square is given by the expression s•s square inches, where s is the length of a side in inches. Write the expressi

grandymaker [24]

This can also be written as A = s^2 and the area would be 49 with a side length of 7.

In order to find this, you can stick 7 into the area equation.

A = s^2

A = 7^2

A = 49

6 0

3 years ago

Nine times nineteen<br> Equals to

Leokris [45]

Answer:

171

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is the image of (12,-9) after a dilation by a scale factor of 1/3 centered at the origin

vladimir2022 [97]

Answer:

(4, -3)

Step-by-step explanation:

You just divide each coordinate by 3.

7 0

3 years ago

4) Choose the correct inequality for this situation.

Ksenya-84 [330]

Answer:

B. 21x + 40 ≤ 124

Step-by-step Explanation:

Maximum amount budgeted = $124 (this means they can't spend more than this)

x = number of people

Cost per head = $21

Given that Mr Walter already spent $40, which is part of the money budgeted, the number of people that can go canoeing cam be expressed with the following inequality:

21x + 40 ≤ 124

(note: the amount total to be spent will either be equal to or greater than $124, because it's the maximum amount budgeted for spending).

6 0

3 years ago

write a linear equation that intersects y=x^2 at two points. Then write a second linear equation that intersects y=x^2 at just o

Liula [17]

We know that $y = x^2$ is a parabola, concave up, with vertex in the origin $(0,0)$

So, we may use three horizontal lines for our purpose: any horizontal line above the x axis will intersect the parabola twice. The x axis itself intersects the parabola once on the vertex, while any horizontal line below the x axis won't intercept the parabola.

Here's the examples:

The horizontal line $y = 4$ intercepts the parabola twice: the system $y = x^2,\ y = 4$ is solved by $x^2=4 \implies x = \pm 2$
The horizontal line $y=0$ intercepts the parabola only once: the system is $y=x^2,\ y=0$ which yields $x^2=0\implies x=0$ which is a repeated solution
The horizontal line $y=-5$ intercepts the parabola only once: the system is $y=x^2,\ y=-5$ which yields $x^2=-5$ which is impossible, because a squared number can't be negative.

5 0

3 years ago