5x-2=3x+8
X=5
That's your answer
Hip Breadths and Aircraft Seats
Engineers want to design seats in commercial aircraft so that they are wide enough to fit 98% of all males. (Accommodating 100% of males would be too expensive.) Men have hip breadths that are normally distributed with a mean of 14.4 in. and a standard deviation of 1.0 in. Find P 98. That is, find the hip breadth for men that separates the smallest 98% from the largest 2%.
(8 times 4) - (2 times 3 = 8) divided by 2
F(-7) = -7 - 10
f(-7) = -17
Hope I helped!
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<span>~ Zoe (Rank:'Genius')</span>
