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fgiga [73]
3 years ago
15

For each part, first decide which of the three methods sections will most easily enable you to sketch the surface. These are the

generalized cylinder method, the surface of revolution method, and the method of slices (traces) for general quadric surfaces. Then apply that method to sketch the surface.
a. x^2 = 4z +8
b. x^2 - 4y^2 – 4z^2 = 16
c. y^2 = x^2 + 2z^2

Mathematics
1 answer:
UkoKoshka [18]3 years ago
6 0

Answer:

Step-by-step explanation:

We use these three methods

1. Generalized cylinder method

2. Surface of revolution method

3. Method of slices general quadratic

1. For A = x² = 4z + 8

We use the method of slices for general quadratic

2. X²-4y²-4z² = 16

We use the generalized cylinder method

3. Y² = z² + 2z²

We use surface of revolution

Please check attachment for answers

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FromTheMoon [43]

Step-by-step explanation:

Let ABCD be a rhombus. So, AC (AC = 14 cm) and BD (BD=48 cm) will be its diagonals. Let us assume that diagonals are intersecting at point O.

Since, diagonals of a rhombus are perpendicular bisector.

\because \: OA  =  \frac{1}{2}  \times AC \\  \\   \therefore \: OA  =  \frac{1}{2}  \times 14 \\  \\   \huge \red{ \boxed{\therefore \: OA  =  7 \: cm}} \\  \\ \because \: OB  =  \frac{1}{2}  \times BD \\  \\ \therefore \: OB  =  \frac{1}{2}  \times 48 \\  \\ \huge \red{ \boxed{\therefore \: OB  = 24 \: cm}} \\  \\ In \:  \triangle OAB, \:  \:  \angle AOB=90° \\  \therefore \: by \: Pythagoras \: Theorem \\ AB= \sqrt{OA^2 +OB^2 }  \\  =  \sqrt{7^2 +24^2 } \\ =  \sqrt{49+576 } \\ =  \sqrt{625 } \\  \huge \orange{ \boxed{\ \therefore \:AB= 25 \: cm.}}

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4 years ago
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KengaRu [80]
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Read 2 more answers
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