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gizmo_the_mogwai [7]
3 years ago
7

OC and OR are similar. Find the length of QP.

Mathematics
1 answer:
Elena L [17]3 years ago
5 0

Given:

Circle C and circle R are similar.

The length of arc AB is s = \frac{22 \pi}{9}

The radius of circle C (AC) = 4 unit

The radius of circle R (QR) =6 unit

To find the length of arc QP.

Formula

The relation between s,  r and \theta is

arclength = 2\pi r \frac{\theta}{360}

where,

s be the length of the arc

r be the radius

\theta be the angle.

Now,

For circle C

Taking r = 4

According to the problem,

2 \pi r \frac{\theta}{360} = \frac{22 \pi}{9}

or, 2r \frac{\theta}{360} = \frac{22}{9} [ eliminating \theta from both side]

or, \theta = \frac{(22)(360)}{(9)(2)(4)}

or, \theta = 110^\circ

Again,

For circle R

Taking, r = 6 and \theta = 110^\circ we get,

The length of arc QP is

arc length = 2\pi (6)(\frac{110}{360} )

or, arclength = \frac{11 \pi}{3}

Hence,

The length of QP is \frac{11 \pi}{3}. Option C.

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genetic experiment with peas resulted in one sample of offspring that consisted of green peas and yellow peas. a. Construct a ​%
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Complete Question

A genetic experiment with peas resulted in one sample of offspring that consisted of 432 green peas and 164 yellow peas. a. Construct a 95% confidence interval to estimate of the percentage of yellow peas. b. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations?

Answer:

The  95%  confidence interval is  0.2392  <  p < 0.3108

No, the confidence interval includes​ 0.25, so the true percentage could easily equal​ 25%

Step-by-step explanation:

From the question we are told that

  The total sample size is  n  =  432 + 164 =596

   The  number of  offspring that is yellow peas is y =  432

   The  number of  offspring that is green peas   is g =  164

   

The sample proportion for offspring that are yellow peas is mathematically evaluated as

        \r p  =  \frac{ 164 }{596}

        \r p  =  0.275

Given the the  confidence level is  95% then the level of significance is mathematically represented as

       \alpha  =  (100 - 95)\%

      \alpha =  5\%  =  0.0 5

The  critical value of  \frac{\alpha }{2} from the normal distribution table is  

      Z_{\frac{\alpha }{2} } = 1.96

Generally the margin of error is mathematically evaluated as

        E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\r p (1- \r p )}{n} }

=>      E = 1.96 * \sqrt{\frac{0.275 (1- 0.275 )}{596} }

=>      E =  0.0358

The  95%  confidence interval is mathematically represented as

      \r p - E  <  p < \r p + E

=>   0.275 -  0.0358  <  p < 0.275 +  0.0358

=>   0.2392  <  p < 0.3108

6 0
3 years ago
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