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noname [10]
3 years ago
5

Find the solution of this system of equations 6x+3y=12 6x-5y=60

Mathematics
1 answer:
olga2289 [7]3 years ago
4 0

Answer:

(5, - 6)

Step-by-step explanation:

Given the 2 equations

6x + 3y = 12 → (1)

6x - 5y = 60 → (2)

Multiply (2) by - 1 and add to (1) will eliminate the term in x

- 6x + 5y = - 60 → (3 )

Add (1) and (3) term by term

(6x - 6x) + (3y + 5y) = (12 - 60)

8y = - 48 ( divide both sides by 8 )

y = - 6

Substitute y = - 6 into (1) or (2) and siolve for x

Using (1), then

6x - 18 = 12 ( add 18 to both sides )

6x = 30 ( divide both sides by 6 )

x = 5

Solution is (5, - 6)

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Answer:

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A bus travels on an east-west highway connecting two cities A and B that are 100 miles apart. There are 2 services stations alon
melamori03 [73]

Answer:

51/4

Step-by-step explanation:

To begin with you have to understand what is the distribution of the random variable. If X represents the point where the bus breaks down. That is correct.  

X~ Uniform(0,100)

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Now, imagine that the D represents the distance from the break down point to the nearest station. Think about this, the first service station is 20 meters away from city A, and the second station is located  70 meters away from city A then the mid point between 20 and 70  is (70+20)/2 = 45 then we can represent D as follows

D(x) =\left\{ \begin{array}{ll}  x  & \mbox{if } 0\leq x \leq 20 \\  x-20 & \mbox{if } 20\leq x < 45\\                70-x & \mbox{if } 45 \leq x \leq 70\\                x-70 & \mbox{if } 70 \leq x \leq 100\\ \end{array}\right.

Now, as we said before X represents the random variable where the bus breaks down, then we form a new random variable Y = D(X), Y is a random variable as well, remember that there is a theorem that says that

E[Y] = E[D(X)] = \int\limits_{-\infty}^{\infty} D(x) f(x) \,\, dx

Where f(x) is the probability mass function of X. Using the information of our problem

E[Y] = \int\limits_{-\infty}^{\infty}  D(x)f(x) dx \\= \frac{1}{100} \bigg[ \int\limits_{0}^{20} x dx +\int\limits_{20}^{45} (x-20) dx +\int\limits_{45}^{70} (70-x) dx +\int\limits_{70}^{100} (x-70) dx  \bigg]\\= \frac{51}{4} = 12.75

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3 years ago
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Talja [164]
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Mama L [17]

Answer:

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I will assume that your system is

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