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2 years ago

Can someone help plz ill give brainiest

Mathematics

1 answer:

Whitepunk [10]2 years ago

7 0

Answer:

402.123859659

Step-by-step explanation:

first we use A=πr2

this gives us A = 16π

Then multiply by 8 to get 128π

128π = 402.123859659

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Solve for the variable (x + 18)° 48°

Mumz [18]

Answer:

=48x+864

Step-by-step explanation:

6 0

2 years ago

What is the multiplicative inverse of -27 and what is the multiplicative inverse for 7/9 and -9/16

liberstina [14]

The multiplicative inverse of a number is the number when you multiply it, it gives you the product of 1.

So for - 27, what number will give us 1 when we multiply it by -27

-27 * -1/27 = 1

So the multiplicative inverse of -27 = -1/27

7/9 * 9/7 = 1

-9/16 * -16/9 = 1

So in essence, just take the number and flip it

-27 = -1 / 27

7/9 = 9/7

-9/16 = -16/9

3 0

2 years ago

The question is in the image! Please help if u can its due really soon

maw [93]

Answer:

5.4

Step-by-step explanation:

3x+38=10x

-3x -3x

38=7x

x=5.4

Brainliest pleaseeeeeee

7 0

2 years ago

Read 2 more answers

The ratio of the number of male lions to female lions in the animal reserve is 21:20. If there are 123 lions in the animal reser

Vanyuwa [196]

21 + 20 = 43

Total is 123, so divide by 43.

123/43 = 2.86 rounded to 3.

(females) 20 x 3 = 60 female lions

7 0

2 years ago

An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed

masya89 [10]

Answer:

$P(X\leq 1) = 0.331$

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

$P(X = x) = \frac{y^xe^{-y}}{x!}$

Where y represents λ (average)

y = 2.3

Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment

Using probability notations;

$P(X\leq 1) = P(X=0) + P(X =1)$

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

$P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}$

$P(X = 0) = \frac{1 * e^{-2.3}}{1}$

$P(X = 0) = e^{-2.3}$

$P(X = 0) = 0.10025884372$

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

$P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}$

$P(X = 1) = \frac{2.3 * e^{-2.3}}{1}$

$P(X = 1) =2.3 * e^{-2.3}$

$P(X = 1) = 2.3 * 0.10025884372$

$P(X = 1) = 0.23059534055$

$P(X\leq 1) = P(X=0) + P(X =1)$

$P(X\leq 1) = 0.10025884372 + 0.23059534055$

$P(X\leq 1) = 0.33085418427$

$P(X\leq 1) = 0.331$

Hence, the required probability is 0.331

6 0

2 years ago