Can someone help plz ill give brainiest
1 answer:
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Answer:
The correct answer is
(0.0128, 0.0532)
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence interval
, we have the following confidence interval of proportions.
In which
Z is the zscore that has a pvalue of
For this problem, we have that:
In a random sample of 300 circuits, 10 are defective. This means that and
Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool.
So = 0.05, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
The correct answer is
(0.0128, 0.0532)