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I am Lyosha [343]
3 years ago
12

Use the properties of real numbers to rewrite the expression. 2/5 * (-7) * 5/2

Mathematics
1 answer:
Mama L [17]3 years ago
4 0

For this case we have the following expression:

\frac{2}{5}*(- 7)*\frac{5}{2}

Using the associative property we can rewrite the expression in the following way:

(\frac{2}{5}*\frac{5}{2})*(-7)

Finally, simplifying we have:

(1) (- 7)

-7

Answer:

Rewriting the expression we have that the result is:

d. -7

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A segment with endpoint M Left parenthesis 5 comma 9 right parenthesis and N Left parenthesis 4 comma 3 right parenthesis is rot
mario62 [17]
Refer to the diagram below

If we draw a line that connects the center of rotation to one of the points, say point N, and take this line as the 0° position, then we need three 'turn' of 90° to get to 270°.

Coordinate of N' (-3, 4)
Coordinate of M' (-9, 5)

3 0
3 years ago
Translation: 4 units left and 4 units up<br> J(−1, −2), A(−1, 0), N(3, −3)
Molodets [167]

Answer:

(-5,2), (-5,4), and (-1,1)

Step-by-step explanation:

3 0
3 years ago
Cory, Josh and Dan went shopping for Halloween treats. Cory bought 3 chocolate pumpkins, 4 masks and 8 candy witches. He spent $
bija089 [108]

Answer:

The cost of chocolate pumpkins is $1.89, masks cost $5.75 and candy witches cost $1.62

Step-by-step explanation:

Let x represent the cost of chocolate pumpkins, y the cost of masks and z the cost of candy witches.

Cory shopping can be represented as:

3x + 4y + 8z = 41.63      (1)

Josh shopping can be represented as:

6x + 2y + 14z = 45.52    (2)

Dan shopping can be represented as:

8x + 3y + 25z = 72.87    (3)

The equations in matrix form is:

\left[\begin{array}{ccc}3&4&8\\6&2&14\\8&3&25\end{array}\right] \left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{c}41.63\\45.52\\72.87\end{array}\right] \\\\\\\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}3&4&8\\6&2&14\\8&3&25\end{array}\right] ^{-1}\left[\begin{array}{c}41.63\\45.52\\72.87\end{array}\right] \\\\\\\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{c}1.89\\5.75\\1.62\end{array}\right]

The cost of chocolate pumpkins is $1.89, masks cost $5.75 and candy witches cost $1.62

7 0
3 years ago
Please help with this question.
Ann [662]

Answer:

I believe the answer is B

Step-by-step explanation:

PLZ MARK BRAINLIEST

3 0
3 years ago
Read 2 more answers
2.06. In a study to estimate the proportion of residents in a certain city and its suburbs who favor the construction of a nucle
DaniilM [7]

Answer:

z=\frac{0.74-0.56}{\sqrt{0.64(1-0.64)(\frac{1}{100}+\frac{1}{125})}}=2.795  

p_v =2*P(Z>2.795)= 0.005  

So if we compare the p value and using any significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the proportions are different at 5% of significance.  

Step-by-step explanation:

Data given and notation  

X_{1}=74 represent the number of residents in a certain city and its suburbs who favor the construction of a nuclear power plant

X_{2}=70 represent the number of people suburban residents are in favor

n_{1}=100 sample 1 selected

n_{2}=125 sample 2 selected

p_{1}=\frac{74}{100}=0.74 represent the proportion of residents in a certain city and its suburbs who favor the construction of a nuclear power plant

p_{2}=\frac{70}{125}=0.56 represent the proportion of suburban residents are in favor

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the proportions are different, the system of hypothesis would be:  

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{74+70}{100+125}=0.64

Calculate the statistic

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.74-0.56}{\sqrt{0.64(1-0.64)(\frac{1}{100}+\frac{1}{125})}}=2.795  

Statistical decision

The significance level provided is \alpha=0.05 ,and we can calculate the p value for this test.  

Since is a two tailed test the p value would be:  

p_v =2*P(Z>2.795)= 0.005  

So if we compare the p value and using any significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the proportions are different at 5% of significance.  

5 0
3 years ago
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