Answer:
100%
Explanation:
No matter how many factors are in the cross, if an 2 purebred (homozygous individuals) are crossed, (one dominant, one recessive) the dominant phenotype will always be displayed.
Imagine a cross with between two individuals true breeding for 6 traits. One shows all dominant genotypes, one shows all recessive genotypes. The only gametes those individuals can pass on will always produce heterozygotes.
AABBCCDDEEFFGG x aabbccddeeffgg
The first individual can only give ABCDEFG alleles. The second individual can only give abcdefg alleles. Therefore, all offspring will be AaBbCcDdEeFfGg, and will therefore express the dominant trait.
Nk cells
^_^
Hope these helps you
The mix of alleles from various genes that end up in the daughter cells is determined by the anaphase 1 of meiosis 1.
Chromosome segregation during meiosis is mirrored in the segregation of alleles. During anaphase, 1 of meiosis 1 homologous chromosomal separation leads to allele segregation.
Chromosomes display autonomous assortment when they are randomly split into daughter cells during meiosis.
<h3>What takes place in anaphase 1?</h3>
During meiosis I, sister chromatids remain together as homologous chromosomes separate. To appreciate the development of germ cells, it is crucial to comprehend how this odd chromosomal segregation behavior came to be. Here, we show that the pattern of chromosomal segregation during meiosis I is determined by the microtubule-kinetochore interactions that are inhibited during prophase I and the premeiotic S phase.
To know more about allele segregation visit:
brainly.com/question/2193571
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