Answer:
there are 5 breeding pairs
Explanation:
Answer:
Explanation:
The missing diagram contained in this question is first attached in the image below.
The objective of this question is to determine how ions migrate when the cells are operating by assuming the solutions are composed of Ni(NO3)2.
From the information provided:
In this instance, the ions tend to move first from cathode to anode in terms of raising the concentration of Ni(2+) at the anode, resulting in the development of a dead cell. The initial concentration of [Ni(2+)] in the anode solution is 1.00 × 10⁻³ M, which gradually increases to 0.5 M, during which both the cathode and the anode possess the same concentration at the same point.
This causes Q(equilibrium constant) to equal 1 as well as log(Q) to equal 0, indicating that the cell is dead.
As a result, the cell will cease to operate, and nothing will migrate from the left to the right side.
Answer:
We need to cross a white eyed female (XwXw) and red eyed male (XRY).
The cross can be shown as:
Xw Xw
XR XRXw (female, red eyed) XRXw (female, red eyed)
Y XwY (male, white eyed) XwY (male, white eyed)
Thus, in the offspring we will have the following phenotype:
Males: White eyed.
Females: Red eyed.
Explanation:
Answer:
C
Explanation:
a. refers to amount of energy passed upwards to each trophic level
b. only counts number of each organism
c. counts total mass of living tissue
d. i'm not familiar with but doesn't look right