<span>for the first part, realize that the hour and minute hands are moving at different rates; in one hour, the minute hands moves all the way around the face of the clock, and thus moves a total of 360 degrees or 2 pi radians; the hour hand moves only 1/12 away around the clock, so covers only 30 degrees or Pi/6 radians.
Now, the LINEAR distance traveled by the tip of each hand is also determined by the length of the hand. In the case of the minute hand, it sweeps out a circle of radius 10 cm, so traces out a circle of radius 10 cm. Since the circumference of a circle is 2*pi*r, the minute hand (remember it made one complete cycle) covers a distance of 2*pi*10cm=20 Pi cm
The hour hand covers only 1/12 a circle, but that circle is only 6 cm in radius, so the distance traveled by the tip of the minute hand is:
1/12 *[2 *pi*r]=1/12*[12*pi]=pi
so the difference is 19pi
for the last part, you should draw a diagram of the two hands, the minute hand is 10 cm in length, the hour hand is 6 cm in length, and they are 30 degrees apart...from that drawing, see if you can figure out the remaining leg of the triangle you can form from them
good luck</span><span>
</span>
Answer:
I answered the question according to "ASA" Angle, side, angle
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Step-by-step explanation:
Note : I'm not a teacher but I'm quite sure about my answer...
Anyway...
If I'm wrong just tell me...
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GOOD LUCK... ❤️
Barry will use the distance formula:
d = √[(x₂ - x₁)² + (y₂ - y₁)²]
d = √[(4 - 3)² + (7 - 1)²]
d = 6.08 units
Try out 64?? Sorry if the answer is incorrect.... I will try to reccommend your question to other people. :)
