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Savatey [412]
3 years ago
15

Point (a,a) lies on the graph of the equation 3y = 2x -4 find the value of a

Mathematics
1 answer:
Igoryamba3 years ago
5 0
Substituting (x, y) with (a, a), since we have:

3a=2a-4, which means that 3a-2a=-4, that is a=-4.

So, the point is (-4, -4).


Remark: a point which lies in the graph of an equation is a solution of that equation. So x=a, y=a satisfies the equation <span> 3y = 2x -4, which makes our substitution legitimate.


Answer: </span>(-4, -4).
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The claim is that the proportion of adults who smoked a cigarette in the past week is less than 0.30​, and the sample statistics
IrinaK [193]

Answer: 0.84

Step-by-step explanation:

let p be the population proportion of adults who smoked a cigarette in the past week.

As per given , we have

H_a: p

Sample size : n= 1491

The sample proportion of adults smoked a cigarette= \hat{p}=\dfrac{x}{n}=\dfrac{462}{1491}=0.30985915493\approx0.31

The test statistic for proportion is given by :-

z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

Substitute all the values , we get

z=\dfrac{0.31-0.30}{\sqrt{\dfrac{0.30(1-0.30)}{1491}}}\\\\=\dfrac{0.01}{\sqrt{0.000141}}\\\\=\dfrac{0.01}{0.011874342087}=0.84261497731\approx0.84

Hence, the value of the test statistic = 0.84

6 0
3 years ago
What is the equation of the line that passes through the points (-9,-6) and (-9, -8)?​
andrey2020 [161]

Answer:

x=-9

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-8-(-6))/(-9-(-9))

m=(-8+6)/(-9+9)

m=-2/0

undefined

x=-9

7 0
2 years ago
I feel so stupid, but I need helping figuring out this problem. I can’t remember how to do it. Can someone help me please
AleksandrR [38]
The answer is C. 
90/105=6/7
Hope this helps!
3 0
2 years ago
PLEASE HELP&gt; I NEED ANSWER ASAP. GEOMETRY
OlgaM077 [116]

Answer:

Angle 4=82 degrees, then i think angle 1 and 3= 98 degrees

Step-by-step explanation:

Angle 2=Angle 4 and 180-82=98

6 0
2 years ago
I need need help on the double. #pawpatrol
worty [1.4K]
K-7.2>2.1.
+7.2 +7.2
------------------
k> 9.3
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3 0
2 years ago
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