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3 years ago

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Mathematics

1 answer:

ANEK [815]3 years ago

8 0

Answer:

Step-by-step explanation:

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Schools, peers, and co-workers are __________ because they influence or shape our self-concept, attitudes, and behaviors.

Bogdan [553]

Answer:

Agents of socialization

Step-by-step explanation:

A <em>total institution</em> is a closed social system where life is organized by norms, rules, schedules, whatever happens, within it it's determined by a single authority. These systems are designed to provide care to a population that is unable to care for themselves, and/or protect society from potential harm, examples of these institutions are mental health facilities, prisons or private boarding schools. Sociologically speaking these institution's purpose is resocialization and/or rehabilitation.
<em>The superego </em>is a component of personality (along with Id and Ego), it holds all of our internalized moral standards and ideals that we acquired from our parents and society it's the sense of right and wrong. It perfects and civilize our behavior.
Socialization is a lifelong process in which we learn about social expectations and how to interact with other people, this socialization occurs during all our lives but the most important period is during childhood, this is where<em> agent of socialization (groups of people responsible for our socialization) like family, school or mass media influence our socialization.</em>
<em>Life-course stages </em>are the sequence of events, roles and age categories that people experience from birth until death, these stages are divided into three main levels of socialization (primary, secondary and adult)

I hope you find this information useful and interesting! Good luck!

3 0

3 years ago

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Today is the 65th day of school. If we are out of 180 days, how do I write this as a

jeka57 [31]

13/36 would be the answer I believe

8 0

3 years ago

Find $\int \dfrac{x}{\sqrt{1-x^4}}$ Please, help

ki77a [65]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2867785

_______________

Evaluate the indefinite integral:

$\mathsf{\displaystyle\int\! \frac{x}{\sqrt{1-x^4}}\,dx}\\\\\\ \mathsf{=\displaystyle\int\! \frac{1}{2}\cdot 2\cdot \frac{1}{\sqrt{1-(x^2)^2}}\,dx}\\\\\\ \mathsf{=\displaystyle \frac{1}{2}\int\! \frac{1}{\sqrt{1-(x^2)^2}}\cdot 2x\,dx\qquad\quad(i)}$

Make a trigonometric substitution:

$\begin{array}{lcl}
\mathsf{x^2=sin\,t}&\quad\Rightarrow\quad&\mathsf{2x\,dx=cos\,t\,dt}\\\\
&&\mathsf{t=arcsin(x^2)\,,\qquad 0\ \textless \ x\ \textless \ \frac{\pi}{2}}\end{array}$

so the integral (i) becomes

$\mathsf{=\displaystyle\frac{1}{2}\int\!\frac{1}{\sqrt{1-sin^2\,t}}\cdot cos\,t\,dt\qquad\quad (but~1-sin^2\,t=cos^2\,t)}\\\\\\
\mathsf{=\displaystyle\frac{1}{2}\int\!\frac{1}{\sqrt{cos^2\,t}}\cdot cos\,t\,dt}$

$\mathsf{=\displaystyle\frac{1}{2}\int\!\frac{1}{cos\,t}\cdot cos\,t\,dt}\\\\\\
\mathsf{=\displaystyle\frac{1}{2}\int\!\f dt}\\\\\\
\mathsf{=\displaystyle\frac{1}{2}\,t+C}$

Now, substitute back for t = arcsin(x²), and you finally get the result:

$\mathsf{\displaystyle\int\! \frac{x}{\sqrt{1-(x^2)^2}}\,dx=\frac{1}{2}\,arcsin(x^2)+C}$ ✔

________

You could also make

x² = cos t

and you would get this expression for the integral:

$\mathsf{\displaystyle\int\! \frac{x}{\sqrt{1-(x^2)^2}}\,dx=-\,\frac{1}{2}\,arccos(x^2)+C_2}$ ✔

which is fine, because those two functions have the same derivative, as the difference between them is a constant:

$\mathsf{\dfrac{1}{2}\,arcsin(x^2)-\left(-\dfrac{1}{2}\,arccos(x^2)\right)}\\\\\\
=\mathsf{\dfrac{1}{2}\,arcsin(x^2)+\dfrac{1}{2}\,arccos(x^2)}\\\\\\
=\mathsf{\dfrac{1}{2}\cdot \left[\,arcsin(x^2)+arccos(x^2)\right]}\\\\\\
=\mathsf{\dfrac{1}{2}\cdot \dfrac{\pi}{2}}$

$\mathsf{=\dfrac{\pi}{4}}$ ✔

and that constant does not interfer in the differentiation process, because the derivative of a constant is zero.

I hope this helps. =)

6 0

3 years ago

Help please i don’t understand

Monica [59]

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Triangles are similar ,

Thus :

$\frac{9}{3} = \frac{6}{x} \\$

$3 = \frac{6}{x} \\$

$\frac{6}{x} = 3 \\$

Inverse both sides

$\frac{x}{6} = \frac{1}{3} \\$

Multiply sides by 6

$6 \times \frac{x}{6} = 6 \times \frac{1}{3} \\$

$x = 2 \times 3 \times \frac{1}{3} \\$

$x = 2$

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7 0

3 years ago

Jessica went to the mall and used 1/6 of her money on lunch. What is the fraction of her money expressed as a decimal?

skad [1K]

The answer to this problem situation would be D.
To solve this problem you would simply divide 1 by 6 (the line between the 1 and 6 in the fraction is a division sign with the denominator always out and the numerator in)
1) 1÷6= 0.1666666666667
Now you traditionally and usually would round up but if the direction says otherwise then round down.
2) 0.17
And 0.17 would be your final answer!

4 0

3 years ago

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