Its true that the cerebral cortex is the highest portion of the brain.
Answer:
Breathing, coloration to skin, beating heart, movement, flowing blood.
Explanation:
Answer:
First of all is ventral: cavity that makes up the thoracic and abdominopelvic cavity ventral: cavity that makes up the thoracic and abdominopelvic cavity
Secondly it is thoracic: chest cavity
And thirdly it is pleural cavities: which consist of ths lung cavity
That is it will encounter tbe parietal layer of the serous membrane first :lines cavity
Explanation:
The organs in the body are safely guarded by the membrane, cavities and sheaths(which has different compartment). They act to protect the organs in the body like lungs.
A person who was shot with a gun, the bullet must pass the body cavities when moving to the lungs. It must first pass through the 3 cavities before it arrives at the lungs that is the ventral cavity, thoracic cavity and the pleural cavity. The serous membrane is usually found within the walls of the thoracic cavity.
Answer:
There are four steps in solving a stoichiometry problem:
Write the balanced chemical equation.
Convert the units of the given substance (A) to moles.
Use the mole ratio to calculate the moles of wanted substance (B).
Convert moles of the wanted substance to the desired units.
Explanation:
(https://socratic.org/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty) This site will give you all the info you need on how to solve it! Gives examples too!
Answer:
XbY
Explanation:
The gene responsible for colorblindness is written as Xb since it is present on the X chromosome. In humans, sons get their X chromosomes from the mother while inheriting the Y chromosome from the father. In the given cross, the genotype of the colorblind mother would be XbXb (the X-linked recessive traits such as colorblindness are expressed in homozygous conditions in females).
She would transmit one copy of "Xb" to her son. The genotype of the father would be "XY" and he will give "Y chromosome" to the son. Therefore, the genotype of the son would be "XbY".
