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3 years ago

Square root negative 50

Mathematics

1 answer:

Mama L [17]3 years ago

3 0

5i square root 2
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Ms smith has 28 sixth graders and 35 7th graders for math.If she wants to break the two grades into identical groups without any

Lina20 [59]

Ms. Smith can make:
1 group of 63, or 63 groups of 1
3 groups of 21, or 21 groups of 3
7 groups of 9, or 9 groups of 7

28+35
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Multiples of 63
1,3,7,9,21,63

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4 years ago

What is x-9over3=2? Need answer bad

Sholpan [36]

To find (x-9)/3=2, we do
(x-9)/3=2
(x-9)/3×3=2×3
x-9=6
x-9+9=6+9
x=15
So, x is 15

3 0

3 years ago

Read 2 more answers

the value of k so that the line Containing the points (-8,k) and (-4,-8) is perpendicular) to the line containing the points (10

In-s [12.5K]

Answer:

$k= \frac{-34}{3}$

Step-by-step explanation:

Step 1 :-

Perpendicular condition :-

Step 1:-

Two non-vertical lines are perpendicular to each other if and only if their slopes are negative reciprocals of each other.

$m_{2} = \frac{-1}{m_{1} }$

$m_{1} m_{2} = -1$

Step 2:-

The given points are (-8,k) and (-4,-8)

$m_{1} = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

finding slope of the first line is $m_{1}$

using formula $m_{1} = \frac{-8-k}{-4+8}$

= $\frac{-8-k}{4}$

finding slope of the second line is $m_{2}$

using formula $m_{2} = \frac{--5+11}{5-10}$

= $\frac{6}{-5}$

Step 3:-

using perpendicular condition

The two lines are perpendicular and their slopes are

$m_{1} m_{2} = -1$

$(\frac{-k-8}{4} )(\frac{-6}{5} )= -1$

simplification,we get solution is

$\frac{6(k+8)}{20} =-1$

$6 k+48 =-20$

$6 k = -20 -48$

$6 k = -68$

$\frac{-68}{6}$

$k= \frac{-34}{3}$

Final answer is

$k= \frac{-34}{3}$

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3 years ago

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qwelly [4]

25 - 9 = 16

16 / 8 = 2

each cost $2

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