This might be wrong but I got .024806509
I don't know if you wanted it rounded but I hope this might have helped.
The answer of your question is x - 4 y=8
<h3>Answer:</h3>
Yes, ΔPʹQʹRʹ is a reflection of ΔPQR over the x-axis
<h3>Explanation:</h3>
The problem statement tells you the transformation is ...
... (x, y) → (x, -y)
Consider the two points (0, 1) and (0, -1). These points are chosen for your consideration because their y-coordinates have opposite signs—just like the points of the transformation above. They are equidistant from the x-axis, one above, and one below. Each is a <em>reflection</em> of the other across the x-axis.
Along with translation and rotation, <em>reflection</em> is a transformation that <em>does not change any distance or angle measures</em>. (That is why these transformations are all called "rigid" transformations: the size and shape of the transformed object do not change.)
An object that has the same length and angle measures before and after transformation <em>is congruent</em> to its transformed self.
So, ... ∆P'Q'R' is a reflection of ∆PQR over the x-axis, and is congruent to ∆PQR.
You're having some formatting problems. You may have to do without the special symbols.
<span>Christopher bought a new watch at the store when they were having a 20% off sale.
</span><span>If the regular price of the watch was $48, what did Chris have to pay after the discount was applied?
Let w represent the cost of the watch. Then the discounted price would be (1.00-0.20)($48) = 0.8($48) = $38.40 (answer)</span>
For these equations, we are going to use the slope formula, as defined below (
is slope and
and
are coordinate points):

We can simply "plug in" the coordinates we are given:


Our answers are:

