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Sati [7]
3 years ago
10

2x-3yi=14+12i how do I find x and y

Mathematics
2 answers:
vladimir1956 [14]3 years ago
7 0
2x-3yi=14+12i 
=> 2x=14; -3yi=12i => x=7; y=-4
egoroff_w [7]3 years ago
4 0

Answer:

The answers are:

x=7\\y=-4

Step-by-step explanation:

In order to determine the answer, we have to know about complex numbers.

The complex numbers have one difference respect on real numbers, they have an imaginary unit i.

In general, a complex number has the next form:

a+b*i

"a" and "b" are real numbers.

We can not add the imaginary part (where it is the imaginary unit) with the real part.

In this case, we have an equality, where in the right side, we can see a complex number and in the left side, we can see two variables and the imaginary unit. We just have to build two equation: one for the real part and other one for the imaginary part.

2x=14\\x=7\\\\-3y=12\\y=-4

Finally, the values of the variables to fulfil the equality are:

x=7\\y=-4

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4 years ago
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3 years ago
Given ΔADC and ΔAEB, What is AE?
chubhunter [2.5K]

Answer:

AE = 43.2 units

Step-by-step explanation:

As per the given question image, it can be seen that in the \triangle ADC \text { and }\triangle AEB :

1. \angle B = \angle C = 90^\circ

2. \angle A is common to both the triangles.

3. Two angles are common, so the third angle \angle E is also equal to \angle D.

All the three angles in the \triangle ADC \text { and }\triangle AEB are equal to each other, hence the triangles are similar.

As per the property of similar triangles, the ratio of their sides will be equal.

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Let side AE = x units

Side AD = AE + ED

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