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2 years ago

2x-3yi=14+12i how do I find x and y

Mathematics

2 answers:

vladimir1956 [14]2 years ago

7 0

2x-3yi=14+12i
=> 2x=14; -3yi=12i => x=7; y=-4

egoroff_w [7]2 years ago

4 0

Answer:

The answers are:

$x=7\\y=-4$

Step-by-step explanation:

In order to determine the answer, we have to know about complex numbers.

The complex numbers have one difference respect on real numbers, they have an imaginary unit $i$ .

In general, a complex number has the next form:

$a+b*i$

"a" and "b" are real numbers.

We can not add the imaginary part (where it is the imaginary unit) with the real part.

In this case, we have an equality, where in the right side, we can see a complex number and in the left side, we can see two variables and the imaginary unit. We just have to build two equation: one for the real part and other one for the imaginary part.

$2x=14\\x=7\\\\-3y=12\\y=-4$

Finally, the values of the variables to fulfil the equality are:

$x=7\\y=-4$

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Ashwin paints 2 murals:

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Also, x indicates the side length of the mural in the classroom. Since the classroom mural is square in shape, the length and breadth of the mural would be x.

Part A: Expression to represents the two binomials to be multiplied to find the area of the hallway mural

Area of the hallway mural = Length of the hallway mural × Breadth of the hallway mural

So Length of the hallway mural = Length of the classroom mural + 7

⇒ Length of the hallway mural = x + 7

Breadth of the hallway mural = Breadth of the classroom mural - 3

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Part B: Area of the hallway mural

Area of the hallway mural = Length of the hallway mural × Breadth of the hallway mural

⇒ Area of the hallway mural = (x + 7) × (x-3)

⇒ Area of the hallway mural = x² + 7x - 3x - 21

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Putting the value x = 8 in the answer of Part B

⇒ Area of the hallway mural = 8² + 4×8 - 21

⇒ Area of the hallway mural = 64 + 4×8 - 21

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hichkok12 [17]

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