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Rzqust [24]
3 years ago
9

Helpppp me ASAP!!!!!!!!!

Mathematics
1 answer:
abruzzese [7]3 years ago
5 0

Answer:

11/1 or 11

Step-by-step explanation:

The scale of the y-axis is 11 and the scale of the x-axis is 1.  As said before the Unit Rate is y/x

If you pick one point, let's say (2,22), that will give you 22/2. If we simplify that fraction you get 11/1 or 11.

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PLEASE HELP ASAP! QUESTION IS IN THE PICTURE! 30 POINTS!
Vadim26 [7]

65 = 12.1+h  the flower is 65 inches.  it has grown 12.1 inches since the last time he measured it.  the last time he measured it, it was height h.


65 = 12.1 + h

subtract 12.1 from both sides

65-12.1 = 12.1 + h- 12.1

52.9 = h

The last time he measured it it was 52.9 inches


5 0
3 years ago
Can someone help please
marysya [2.9K]

I would say B. The mean is a good measure of central tendency.

I hope this helps!


6 0
3 years ago
Roots of Quadratics 50 PTS!!!
noname [10]

The values of k for the different quadratic equation solutions are as follows

a  the equation 2x² - x + 3k = 0 has two distinct real roots

  • k < 1/24

b. the equation 5x² - 2x + (2k − 1) = 0 has equal roots

  • k = 3/5

ci the equation -x² + 3x + (k + 1) = 0 has real roots

  • k > -3.25

d the equation 3kx² - 3x + 2 = 0 has no real solutions

  • k < ± 1.633

<h3>How to solve quadratic equations to get different answers</h3>

Quadratic equations of the form ax² + bx + c = 0 is solved using the formula

-b+\frac{\sqrt{b^{2}-4ac } }{2a}     OR     -b-\frac{\sqrt{b^{2}-4ac } }{2a}

The equation b² - 4ac is called the discriminant and it is used as follows

To solve the equation and get two real roots: 2x² - x + 3k = 0

  • b² - 4ac > 0

substituting the values gives

(-1)² - 4 * 2 * 3k > 0

1 - 24k > 0

1 > 24k

divide through by coefficient of k

k < 1/24

To solve the equation and get equal roots: 5x² - 2x + (2k − 1) = 0

  • b² - 4ac = 0

substituting the values gives

(-2)² - 4 * 5 * (2k - 1) = 0

4 - 40k + 20 = 0

-40k = -24

divide through by coefficient of k

k = 3/5

To solve the equation and get real roots  -x² + 3x + (k + 1) = 0

  • b² - 4ac > 0

substituting the values gives  

(3)² - 4 * -1 * (k+1) > 0

9 + 4k + 4> 0

4k > -13

divide through by coefficient of k

k > -3.25

To solve the equation and get  no real solutions  3kx² - 3x + 2 = 0

  • b² - 4ac < 0

substituting the values gives  

(-3)² - 4 * 3k * 2 < 0

9 - 24k² > 0

9 > 24k²

divide through by coefficient of k²

k² < 24/9

k < ± 1.633

Learn more about roots of quadratic equations: brainly.com/question/26926523

#SPJ1

4 0
1 year ago
Read 2 more answers
CAN SOMEONE HELP PLEASE!!
grandymaker [24]
The predicted time remaining has decreased by 30 years, so the second one would be the answer
3 0
3 years ago
SOS HURRY
Burka [1]

First, by using the distance formula for just one side, we can find the length of all sides (a square has 4 equal sides.) Then, we can apply the area of a square formula, which is a^2.

Distance formula:

\sqrt{(x.2 - x.1)^{2} + (y.2 - y.1)^{2}}

√((-2 + 5)^2 + (-8 + 4)^2)

√((3)^2 + (4)^2)

√9 + 16

√25

5

The side lengths of the square are each equal to 5, and by applying the formula for area, we can find the area of the square.

5^2 = 25

<h3>The area is 25.</h3>
3 0
3 years ago
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