Answer:
a^(2m) + 2 a^m b^ (n-1) + b^ ( 2n -2)
Step-by-step explanation:
( a^m + b^(n-1) )( a^m + b^(n-1) )
FOIL
first: a^m a^m = a^ 2m
outer: a^m b^ n-1
inner a^m b^ n-1
last : b^ n-1 b^ n-1 = b^ ( 2n -2)
Add together
a^(2m) + 2 a^m b^ (n-1) + b^ ( 2n -2)
Answer:
$20.40
Step-by-step explanation:
I LOOKED IT UP
Answer:
A.
Step-by-step explanation:
Assuming the 3/8 markers are counting the lines on the number line, not the chunks in between the lines, there are 7 markers that are in the shaded area and another half distance between two markers at the end.
Hello!
So, according to the problem, the heart rate of a bear during hibernation is its original amount.
So we can write an equation to help us understand this.
of sr = 28
We can use inverse to make this easier to solve. 2 × 28 = sr.
So, in simple form, we multiply.
28 × 2 = 56
Our final answer would be:
A bears heart rate during the summer would be 56 beats per minutes.
<em>waffletowne. </em>
They both have the same variable(s) and equal the same thing