2x^2 - quadratic - monomial
-2 - constant - monomial
3x - 9 - linear - binomial
-3x^2 - 6x + 9 - quadratic - trinomial
Step 1) Draw a line from point F to point S. A rectangle forms (rectangle FSCW)
Step 2) Find the area of this rectangle. The area is 18 square units because it is 2 units high and 9 units across (9*2 = 18). You can count out the spaces or you can note how we go from x = -4 to x = 5 so subtracting the values gives -4-5 = -9 which has an absolute value of 9.
Step 3) Find the area of triangle FSN. The base is 9 units and the height is 6 units (count out the spaces or subtract y values). So the area is A = b*h/2 = 9*6/2 = 54/2 = 27
Step 4) Add up the area of the rectangle to the area of the triangle: 18+27 = 45
Final Answer: 45 square units
note: another way to find the answer is to find the area of rectangle WABC where point A is at (-4,4) and point B is at (5,4). Then subtract off the triangular areas of AFN and BNS
Answer is: 50.4%. You have to take 30% off of 72%. Easiest way is to find 10% of 72 (7.2) and multiply that by 3 (=21.6). Then minus this off the original price (72 - 21.6 = 50.4)
1 and 18
1 × 18 = 8
1+ 18 = 19
Area = (h/2)(a +b)
where h = distance between the 2 parallel line segments and a and b are the lengths of these 2 line segments.
