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valentinak56 [21]
3 years ago
8

The mean number of hours of part-time work per week for a sample of 526526 college students is 2828. If the margin of error for

the population mean with a 99%99% confidence interval is 2.22.2, construct a 99%99% confidence interval for the mean number of hours of part-time work per week for all college students.
Mathematics
1 answer:
sveta [45]3 years ago
4 0

Answer:

The 99% confidence interval for the mean number of hours of part-time work per week for all college students is between 25.8 and 30.2.

Step-by-step explanation:

A confidence interval has the following format.

\mu_{x} \pm M

In which \mu_{x} is the mean of the sample and M is the margin of error.

In this problem, we have that:

\mu_{x} = 28, M = 2.2

\mu_{x} - M = 28 - 2.2 = 25.8

\mu_{x} + M = 28 + 2.2 = 30.2

The 99% confidence interval for the mean number of hours of part-time work per week for all college students is between 25.8 and 30.2.

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A bag contains cars numbered from 1 to 14. Find the Probability of:
pochemuha

A)

Prime numbers and numbers with a multiple of four that are between 1 and 14 include: 1, 2, 3, 4, 5, 7, 8, 12, 13.

There are 9 numbers listed.

9/14 = ~0.64285... or roghly 65.3%

B) Numbers between 1 and 14 with the multiples of 2 or 3 include: 2, 4, 6, 8, 9, 10, 12, 14.

There are 8 numbers listed.

8/14 = ~0.5714... or, about 57.14%

C) 3 and 4 is a list of two numbers.

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D) There is a total of  numbers equal to or less than 8 in a list of 1 and 14.

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3 years ago
What is the following number in scientific notation?<br><br> 56.71
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6 0
3 years ago
Which shortcut can be used to prove the triangles are congruent?
Gemiola [76]

Answer:

Option 2: AAS is the right answer

Step-by-step explanation:

In the diagram, two triangles are given with two angle measurements and one non-included side.

It can also be seen that the respective angles of both triangles have same measurement and the non-included side is also congruent.

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Use partial fractions to find the indefinite integral. (Remember to use absolute values where appropriate. Use C for the constan
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Answer:

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Step-by-step explanation:

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Should be

∫x²/(x²−20x−125)dx

First of all let's factorize the denominator.

x²−20x−125= x²+5x-25x-125

x²−20x−125= x(x+5) -25(x+5)

x²−20x−125= (x-25)(x+5)

∫x²/(x²−20x−125)dx= ∫x²/((x-25)(x+5))dx

x²/(x²−20x−125) =x²/((x-25)(x+5))

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Let x= -5

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x²/((x-25)(x+5))= 125/6(x-25) -5/6(x+5)

∫x²/(x²−20x−125)dx

=∫125/6(x-25) -∫5/6(x+5) Dx

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4 years ago
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Answer:

C

Step-by-step explanation:

8 divided by 9 = 0.8888...

5 0
3 years ago
Read 2 more answers
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