Answer:
(-4, 3)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
6x + 8y = 0
-7x + y = 31
<u>Step 2: Rewrite Systems</u>
-7x + y = 31
- Add 7x to both sides: y = 7x + 31
<u>Step 3: Redefine Systems</u>
6x + 8y = 0
y = 7x + 31
<em />
<u>Step 4: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 6x + 8(7x + 31) = 0
- Distribute 8: 6x + 56x + 248 = 0
- Combine like terms: 62x + 248 = 0
- Isolate <em>x </em>term: 62x = -248
- Isolate <em>x</em>: x = -4
<u>Step 4: Solve for </u><em><u>y</u></em>
- Define equation: -7x + y = 31
- Substitute in <em>x</em>: -7(-4) + y = 31
- Multiply: 28 + y = 31
- Isolate <em>y</em>: y = 3
First you do the top
8n+3n-7=8*2+3*2-7=16+6-7= 22-7=15
Then you found out the bottom
6*2n-3(n-1)=6*2*2-3(2-1)=6*2*2-3*1=6*4-3*1=24-3*1=24-3=21
15/21 is your answer.
Hope this helps! :)
Answer:
i cant help that much but u can try using photomath
About 6.5 I believe, I looked it up and a gross was a total of 144 of something, also known as a dozen dozen.
Answer/Step-by-step explanation:
Let's solve your equation step-by-step.
4−(2y+5)=3(1−4y)
Step 1: Simplify both sides of the equation.
4−(2y+5)=3(1−4y)
4+−1(2y+5)=3(1−4y)(Distribute the Negative Sign)
4+−1(2y)+(−1)(5)=3(1−4y)
4+−2y+−5=3(1−4y)
4+−2y+−5=(3)(1)+(3)(−4y)(Distribute)
4+−2y+−5=3+−12y
(−2y)+(4+−5)=−12y+3(Combine Like Terms)
−2y+−1=−12y+3
−2y−1=−12y+3
Step 2: Add 12y to both sides.
−2y−1+12y=−12y+3+12y
10y−1=3
Step 3: Add 1 to both sides.
10y−1+1=3+1
10y=4
Step 4: Divide both sides by 10.
10y
10
=
4
10
y=
2
5
Answer:
y=
2/5
yw