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LUCKY_DIMON [66]
3 years ago
9

3r+2<5 or 7r-10>60 please help me with this problem I have been stumped for awhile

Mathematics
1 answer:
MariettaO [177]3 years ago
7 0
First we have to simplify

3r + 2 < 5
subtract 2 from each side then divide by 3
r < 1

7r - 10 > 60
add ten to both sides. divide by 7.
r > 10

answer: r<1 or r>10

if you have to graph, you should have a number line going from 0 to 11. You should put an open circle on 1 and an open circle on 10. Shade to the left from the open circle on 1, and then shade from the right from the open circle on 10.

Your union should look like this:
(-♾, 1)U(10,+♾)
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Solve this system of linear equations. separate x and y values with a comma. 7x=-67-11y 5x=-73-11y​
Aleks [24]

Answer:

3, -8

(x is equal to 3 and y is equal to -8)

Step-by-step explanation:

<u>The system:</u>

{ 7x=-67-11y

{ 5x=-73-11y​

<u>Finding a value for x:</u>

7x=-67-11y -> x = -\frac{67}{7} - \frac{11y}{7}

<u>Solving for y by plugging in our x:</u>

[Equation] 5x = -73 -11y​

[Plug-in] 5(-\frac{67}{7} - \frac{11y}{7}) = -73 -11y​

[Distribute the 5] -\frac{335}{7} - \frac{55y}{7} = -73 -11y​

[Multiply by 7] 7 (-\frac{335}{7} - \frac{55y}{7}) = (-73 -11y​) 7

[Simplify] -335 - 55y = -511 - 77y

[Add 335 and 77y to both sides] 22y = -176

[Divide by 22] y = -8

<u>Plug in our y to solve for x:</u>

5x = -73 -11y​

5x = -73 -11(-8)

5x = -73 + 88

5x = 15

x = 3

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

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Sophia has 47 jelly beans in a bag she gives away 15 jelly beans her friends? I need help againSorry​
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Answer:

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Step-by-step explanation:

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2 years ago
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What is the total resistance of a parallel circuit that has two loads? Load one has a resistance of 10 ohms. Load two has a resi
Romashka-Z-Leto [24]

Answer:

The total resistance is 7.0588\Omega

Step-by-step explanation:

Attached please find the circuit diagram. The circuit is composed by a voltage source and two resistors connected in parallel: R_1=10\Omega and R_2=24\Omega.

First step: find the total current

For finding the current that the voltage source can provide, you must find the current consumed by each load and then add both. To do that, take first into account that the voltage is the same for both resistors (R_1 and R_2).

  • I_{R_1}=\frac{V_S}{R_1}
  • I_{R_2}=\frac{V_S}{R_2}

The total current is:

I_{TOTAL}=I_{R_1}+I_{R_2}=\frac{V_S}{R_1}+\frac{V_S}{R_2}=\frac{R_2\cdot V_S+R_1\cdot V_S}{R_1\cdot R_2}

I_{TOTAL}=V_S\cdot \frac{R_1+R_2}{R_1\cdot R_2}

Now, the total resistance (R_{TOTAL}) would be the voltage divided by the total current:

R_{TOTAL}=\frac{V_S}{I_{TOTAL}}

If you replace I_{TOTAL} by the expression obtained previously, the total resistance would be:

R_{TOTAL}=\frac{V_S}{V_S\cdot \frac{R_1+R_2}{R_1\cdot R_2}}

After simplifying the terms you should get:

R_{TOTAL}=\frac{R_1\cdot R_2}{R_1 + R_2}}

Now, you must replace the values of the resistors:

R_{TOTAL}=\frac{(10\Omega )\cdot (24\Omega)}{10\Omega + 24\Omega}}=\frac{120}{17}\Omega=7.0588\Omega

Thus, the total resistance is 7.0588\Omega

3 0
3 years ago
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