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slega [8]
3 years ago
5

What's the perimeter of a semicircle with a radius of 3 cm

Mathematics
1 answer:
e-lub [12.9K]3 years ago
6 0
Radius=3cm, so diameter=6cm
(\pi \times 6) + 6
= 24.85
2d.p
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Can somebody help me with this
Lubov Fominskaja [6]
Nope lol , don't even know what the dang
question is

8 0
4 years ago
Im so confused please help with 5 and 6
Drupady [299]

Answer:

5)102,78

6)56,56

<em><u>See</u></em><em><u> </u></em><em><u>THE</u></em><em><u> </u></em><em><u>IMAGE</u></em><em><u> </u></em><em><u>FOR</u></em><em><u> </u></em><em><u>SOLUTION</u></em><em><u> </u></em>

8 0
3 years ago
Read 2 more answers
Does anybody know how to do time with exponential decay
My name is Ann [436]
<span>From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

b_n=0.12\times b_{n-1}

Why does this work? Initially, you start with 500 mL of air that you breathe in, so b_1=500\text{ mL}. After the second breath, you have 12% of the original air left in your lungs, or b_2=0.12\timesb_1=0.12\times500=60\text{ mL}. After the third breath, you have b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}, and so on.

You can find the amount of original air left in your lungs after n breaths by solving for b_n explicitly. This isn't too hard:

b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots

and so on. The pattern is such that you arrive at

b_n=0.12^{n-1}b_1

and so the amount of air remaining after 50 breaths is

b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}

which is a very small number close to zero.</span>
5 0
3 years ago
25 points! pls show work if can!!!!!!!!
Nataliya [291]

Answer: 8.4

Step-by-step explanation:

15-6.6

3 0
3 years ago
Read 2 more answers
What is the equation of a line parallel to the line y = 4x + 7 and passes through the point (3, 0)?
KATRIN_1 [288]
Two lines to be parallel their slopes have to be equal. 

so m1 = m = 4


y = mx + b ( Slope intercept form)


y = 4x + b

(3,0) is on the line:

0 = 12 + b

b = -12

y = 4x - 12 
5 0
3 years ago
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