Answer: A dragon name could be name Holls and at level 14 and can breathe fire
Explanation:
Answer:
<h2>iv. NINGUNO DE LOS ANTERIORES</h2>
Explanation:
<h2>Hola</h2>
Well I would think all of them in some way. For the first one, students need to collect data (whether it’s mathematical, scientific, etc.) to answer a question. For the second one, they may need to know how much money is in there bank account or they may need to calculate a sale to order the item. For the third one, they may need statistical data to support a position. For the last one, a student could use technological data to be able to solve their problem sorting documents.
Answer:
#part 1
#read the amount
amount=int(input("enter the amount:"))
#find the dollars
doll=int(amount/100)
// find the cents
cent=amount%100
#print output
print("{} dollars and {} cents.".format(doll,cent))
#part 2
#read a floating point
temperature=float(input("enter the temperature:"))
#part 3
#read a word
firstWord=input("enter a word:")
Explanation:
In part 1, read amount and the find the dollars with the help of "/" operator. Then find the cents with "%" operator and print both.In part 2, read a point and cast it to float then assign it to variable "temperature".In part 3,Read a word and assign it to variable "firstWord".
Output:
enter the amount:4321
43 dollars and 21 cents.
enter the temperature:12.5
enter a word:hello
Answer:
Check the explanation
Explanation:
223.1.17/24 indicates that out of 32-bits of IP address 24 bits have been assigned as subnet part and 8 bits for host id.
The binary representation of 223.1.17 is 11011111 00000001 00010001 00000000
Given that, subnet 1 has 63 interfaces. To represent 63 interfaces, we need 6 bits (64 = 26)
So its addresses can be from 223.1.17.0/26 to 223.1.17.62/26
Subnet 2 has 95 interfaces. 95 interfaces can be accommodated using 7 bits up to 127 host addresses can represented using 7 bits (127 = 27)
and hence, the addresses may be from 223.1.17.63/25 to 223.1.17.157/25
Subnet 3 has 16 interfaces. 4 bits are needed for 16 interfaces (16 = 24)
So the network addresses may range from 223.1.17.158/28 to 223.1.17.173/28
