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astraxan [27]
3 years ago
6

Resize vector countDown to have newSize elements. Populate the vector with integers {newSize, newSize - 1, ..., 1}. Ex: If newSi

ze = 3, then countDown = {3, 2, 1}, and the sample program outputs:
#include
#include
using namespace std;
int main() {
vector countDown(0);
int newSize = 0;
int i = 0;
newSize = 3;
STUDENT CODE
for (i = 0; i < newSize; ++i) {
cout << countDown.at(i) << " ";
}
cout << "Go!" << endl;
return 0;
}
Computers and Technology
1 answer:
strojnjashka [21]3 years ago
4 0

Answer:

Following are the code to the given question:

#include <iostream>//defining header file

#include <vector>//defining header file

#include <numeric>//defining header file

using namespace std;

int main()//main method

{

vector<int> countDown(0);//defing an integer array variable countDown

int newSize = 0;//defing an integer variable newSize that holds a value 0

int i = 0;//defing an integer variable i that initialize with 0

newSize = 3;// //use newSize to hold a value

countDown.resize(newSize,0);// calling the resize method that accepts two parameters

for (i = 0; i < newSize; ++i)//defining a loop that reverse the integer value

{

countDown[i] = newSize -i;//reverse the value and store it into countDown array

cout << countDown.at(i) << " ";//print reverse array value

}

cout << "Go!" << endl;//print message

return 0;

}

Output:

3 2 1 Go!

Explanation:

In the given code inside the main method an integer array "countDown" and two integer variables "newSize and i" is declared that initializes a value that is 0.

In the next step, an array is used that calls the resize method that accepts two parameters, and define a for a loop.

In this loop, the array is used to reverse the value and print its value with the message.

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Answer:

The code to this question can be given as:

Code:

public interface Test  //define interface  

{

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check .

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}

Explanation:

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The geographic coordinate system is used to represent any location on Earth as a combination of latitude and longitude values. T
Pachacha [2.7K]

Answer:

Here is the script:  

function dd = functionDMS(dd)  

prompt= 'Enter angle in DD form ';

dd = input(prompt)

while (~checknum(dd))

if ~checknum(dd)

error('Enter valid input ');

end

dd = input(prompt)

end  

degrees = int(dd)

minutes = int(dd - degrees)

seconds = ( dd - degrees - minutes / 60 ) * 3600  

print degrees

print minutes

print seconds

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Explanation:

The script prompts the user to enter an angle in decimal degree (DD) form. Next it stores that input in dd. The while loop condition checks that input is in valid form. If the input is not valid then it displays the message: Enter valid input. If the input is valid then the program converts the input dd into degrees, minutes and seconds form. In order to compute degrees the whole number part of input value dd is used. In order to compute the minutes, the value of degrees is subtracted from value of dd. The other way is to multiply remaining decimal by 60 and then use whole number part of the answer as minutes. In order to compute seconds subtract dd , degrees and minutes values and divide the answer by 60 and multiply the entire result with 3600. At the end the values of degrees minutes and seconds are printed. In MATLAB there is also a function used to convert decimal degrees to degrees minutes and seconds representation. This function is degrees2dms.

Another method to convert dd into dms is:

data = "Enter value of dd"

dd = input(data)

degrees = fix(dd);

minutes = dd - degrees;

seconds = (dd-degrees-minutes/60) *3600;

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