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Rama09 [41]
3 years ago
8

What is q? For this 30 and 60, 90 angle?

Mathematics
1 answer:
Effectus [21]3 years ago
8 0
30 60 90 triangle
ratio of short leg : long leg = a : a√3

Given long leg = 9 cm
so
short leg = 9 / √3
= 3√3
= √27
= 27^(1/2)           <..........(radical form)

Hope it helps.
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(Score for Question 2: ___ of 5 points)
GuDViN [60]

Answer:

Answer:

Since you don't show your triangles, I'm guessing it is this one...?

△DWP  D = (-2, 4), W = (-1, 2), P = (3, 3)

△MJS  M = (-4, -4), J = (-2, -3), S = (-3, 1)

There are 2 steps:

1. 90° counterclockwise rotation about the origin

2. Translation downward 2 units

Step-by-step explanation:

1. 90° counterclockwise rotation about the origin = (x, y) to (-y, x),

D moves from (-2, 4) to (-4, -2)

W moves from (-1, 2) to (-2, -1)

P moves from (3, 3) to (-3, 3)

2. Translation downward 2 units = (x, y) to (x, y-2),

D moves from (-4, -2) to (-4, -4) = M

W moves from (-2, -1) to (-2, -3) = J

P moves from (-3, 3) to (-3, 1) = S

Therefore △DWP IS congruent to △MJS.

4 0
3 years ago
Use this equation to find dy/dx. 3y cos x = x2 + y2
Art [367]
Given: 3y cos x = x² + y²

Define y' =  \frac{dy}{dx}

Then by implicit differentiation, obtain
3y' cos(x) - 3y sin(x) = 2x + 2y y'
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Answer:
\frac{dy}{dx} =  \frac{2x+3y \, sin(x)}{3cos(x)-2y}
5 0
3 years ago
How do I simplify this?
WINSTONCH [101]

Answer:

sorry ... good luck tho.....

6 0
3 years ago
Can you guys help me?
denis-greek [22]
Pretty sure you have to use the Pythagorean Theorem.
a^2+b^2=c^2

So you would plug in your numbers that you already have (6 and 10) But notice that 10 is the hypotenuse (longest side) so
6^2+x=10^2

Then you would solve it and you should end up with 11.6619
6 0
3 years ago
I’m confused on where to shade these equations? I can do the first 2 but then the last 2 throw me off... I have to shade the are
tigry1 [53]

I’m not sure the answer but go into a webpage called Desmos and it will show you

4 0
3 years ago
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