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Dvinal [7]
3 years ago
12

Determine whether the given value is a solution of the equation. 36 = k 6 ; k = 6 6 a solution of 36 = k 6 .

Mathematics
1 answer:
Mila [183]3 years ago
4 0

Answer:

Yes: the variable K would equal "6"

Step-by-step explanation:

After you set you equation up, you have to isolate the given variable. To do that you have to do the recipriocal (6k-multiplying) which would be division. You would divide k = 36 ÷ 6 . that isolates the variable ,which you would then solve. k = 6 .

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Write your answer as a whole number and remainder.530/34
arsen [322]
Hey, Zalah. For my answer, I simplified 530/34. Which equals <span>15.58824. Hope this helps! :) </span> 
3 0
3 years ago
Can anyone help me with this.
Minchanka [31]

Answer:

a) third; from left most graph

b) fourth; right most graph

Step-by-step explanation:

Part a)

The graph is between the speed and time.

Nicole begin jogging faster and faster i.e. speed is increasing w.r.t time thus we have linear line in beginning.

Then she hits a comfortable speed and stayed at it i.e. speed remained constant for that time. Thus we have a straight line.

After that she gradually slows down,i.e speed is decreasing w.r.t time. Thus we have decreasing linear line.

So the graph shape is linear line with increasing slope-a constant straight line-linear line with decreasing slope

which is the third; from left most graph in option

Part b)

The graph is between Distance to campus and time.

As Dale is hiking towards campus, distance should decrease w.r.t time.

In beginning, he is hiking at constant speed towards campus thus the distance towards the campus is decreasing w.r.t time. We get a decreasing linear line.

*Note: here constant speed is not important, instead hiking towards i.e. the direction is important because of the campus distance covered

Then he sees a snake and turn and runs the other way. Thus now the distance towards the campus is increasing. And we get increasing linear line.

*Note running other way is important because of the campus distance covered

After that, he sits for a while i.e he stops and so the distance towards campus also become constant w.r.t time. we get a straight line on the graph.

So the graph shape is linear line with decreasing slope-linear line with increasing slope-a constant straight line

which is the right-most graph in option !

4 0
3 years ago
Help me out please?<br>chapter : exponents and powers​
belka [17]

Answer:

\frac{125}{27}

Step-by-step explanation:

\frac{2^{-4} \times 15^{-3} \times 625}{5^2 \times 10^{-4}}

Lets expand all the composite numbers into prime numbers.

=> \frac{2^{-4} \times (3^{-3} \times 5^{-3}) \times 5^4}{5^2 \times (2^{-4} \times 5^{-4})}

Lets cancel 2^{-4} from numerator and denominator.

=> \frac{3^{-3} \times 5^{-3} \times 5^4}{5^2 \times 5^{-4}}

Using laws of exponents , lets solve this.

=> \frac{3^{-3} \times 5^{(-3 + 4)}}{5^{( 2 - 4)}}

=> \frac{3^{-3} \times 5^{1}}{5^{-2}}

=> 3^{-3} \times 5^{[1 - (-2)]}

=> 3^{-3} \times 5^{3}

=> \frac{5^3}{3^3} = \frac{125}{27}

4 0
3 years ago
Read 2 more answers
Two trains leave a city at 3 P.M. One train goes east at a constant rate of 70 mph. The other goes west at a rate of 62 mph. How
andrey2020 [161]

Answer:

4 hours

Step-by-step explanation:

The general formula for distance, rate and time is:

d = rt, where distance is the product of rate multiplied by time

Given that one train is moving at a rate of 70 mph and one is moving at a rate of 62 mph in the opposite direction, the combined distance over time is equal to 528 miles.  Using the variable 't' for time:

70t + 62t = 528

Combine like terms: 132t = 528

Divide both sides by 132: 132t/132 = 528/132  or t = 4 hours

8 0
3 years ago
Read 2 more answers
Round to the underlined place.<br>​
pickupchik [31]

Answer:

the answer would be 8.38

6 0
3 years ago
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