Answer:
x = -19
Step-by-step explanation:
The interval where the function is nonlinear and decreasing is 0 < x < 4
<h3>How to determine the interval where the function is nonlinear and decreasing?</h3>
The straight lines on the graph are the intervals where the graph is linear
This means that the straight lines on the graph will not be considered
Considering the curve, the graph decrease from x = 0 to x = 4
This can be rewritten as:
0 < x < 4
Hence, the interval where the function is nonlinear and decreasing is 0 < x < 4
Read more about function intervals at:
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F(x)=5x^2 Has minimum (0,0)
g(x) = f(x) + 2 Shifts the graph two units up, then the minimum is 2+0=2.
h(x) = g(x+4) Shifts the graph four units left, then the minimum is at 0-4 = -4.
Then h(x) = 5(x+4)^2 + 2 has the minimum (-4,2)
And p(x) = -5(x+4)^2 + 2 has the maximum (-4,2)
The answer is B, 10.
Step-by-step explanation: You plug in the values where the variables are, then follow PEMDAS, beginning with 5 times 3.
Answer:
y = -4/5x + 5
Step-by-step explanation:
Slope-Intercept Form: y = mx + b
Step 1: Write equation in slope-intercept form
5y = -35 - 4x
y = -7 - 4/5x
Step 2: Write parallel line equation
y = -4/5x + 5
A parallel line is a line that has the same slope as the previous equation but a different y-intercept. They never intersect.
