Question

How do I solve this question

Answer 1

Answer:

Part 1) $[(250)^{2}+(-400)^{2}+(-250)^{2}+(350)^{2}+(100)^{2}+(-50)]=420,000$

Part 2) The variance is equal to $Variance=70,000$

Part 3) $Standard\ Deviation=265$

Step-by-step explanation:

step 1

Find the mean of the areas

we have

$[2,400,1,750,1,900,2,500,2,250,2,100]$

To find the mean sum all the values and divide by the number of values

The number of values is 6

so

$[2,400+1,750+1,900+2,500+2,250+2,100]/6=2.150$

The Mean is $2.150$

step 2

For each number subtract the Mean

$[(2,400-2,150),(1,750-2,150),(1,900-2,150),(2,500-2,150),(2,250-2,150),(2,100-2,150)]$

$[(250),(-400),(-250),(350),(100),(-50)]$

step 3

Find the Variance

To calculate the Variance, take each difference, square it, and then average the result

$[(250)^{2}+(-400)^{2}+(-250)^{2}+(350)^{2}+(100)^{2}+(-50)]=420,000$

$Variance=420,000/6=70,000$

step 4

Find the standard deviation

The Standard Deviation is just the square root of Variance

so

$Standard\ Deviation=\sqrt{70,000} =265$