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2 years ago

Determine if the following system of equations has no solutions, infinitely many

Mathematics

1 answer:

DochEvi [55]2 years ago

8 0

Answer:

There is one solution

Step-by-step explanation:

2x + y = -1

8x + 3y = -2

Multiply the first equation by -4

-8x -4y = 4

Then add the equations together to eliminate x

-8x -4y = 4

8x + 3y = -2

--------------------

-y = 2

Multiply by -1

y =-2

Now find x

2x+y =-1

2x+-2 =-1

Add 2 to each side

2x-2+2=-1+2

2x=1

Divide by 2

x = 1/2

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fomenos

Step-by-step explanation:

Answer(1):

Law of Cosines.

Answer(2):

since side "c" is missing so we will write formula used for side "c"

$c^2=a^2+b^2-2ab\cdot\cos\left(C\right)$

Answer(3):

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Check the attached picture for the list of formulas:

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3 years ago

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2 years ago

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nadezda [96]

Answer:

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Step-by-step explanation:

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