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stira [4]
3 years ago
11

Solve the simultaneous equation: 3x+y=-4 3x-4y=6

Mathematics
1 answer:
Verdich [7]3 years ago
7 0

3x+y=-4

3x-4y=6

--------------subtract

5y = -10

y = -2

Substitute y = -2 into 3x + y = -4

3x + (-2) = -4

3x - 2 = -4

3x = -2

 x = -2/3

Answer

Solution x = -2/3, y = - 2 OR (-2/3 , - 2)

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The question is:
saul85 [17]
f(x) = \sqrt{x+1} \\ y = \sqrt{x+1} \ or \ y^2 = x+1 \ or \ x = y^2 - 1 \\ Therefore, \ f^{-1}(x)=x^2 - 1

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