Answer:
35C12 = 834451800
Step-by-step explanation:
.............
Answer:
Gina is 12 years old
Step-by-step explanation:
First, we will have to write these statements mathematically and then solve.
Let Gina's age be x, let Gina's brother's age be y and let Gina's sister's age be z.
The second statement"Gina's older sister is twice Gina's age" can be mathematically written as: z =2 x ---------------------------(1)
The next statement "Gina's brother is half Gina's age" can be mathematically written as y =
---------------------------------------(2)
Then the next statement "the sum of their ages is 42" can be mathematically written as: x + y + z = 42 ----------------------------(3)
We can now proceed to solve;
Substitute equation (1) and equation(2) into equation (3)
x + y + z = 42
x +
+ 2x = 42
Multiply through by 2
2x + x + 4x = 84
7x = 84
Divide both-side of the equation by 7
= 
x = 12
Therefore, Gina is 12 years old
Answer:
The three digit number = 951
Step-by-step explanation:
Let suppose the numbers are:
= abc
According to given condition:
a+ b + c = 15 -------------eq1
Also, given the difference between the first two digit = the difference between the last two digits:
==> l a-b l = l b-cl
==> (a-b) = (b-c)
==> (a+c) = 2b
Now we will substitue in eq1
==> a+ b + c = 15
==> 2b + b = 15
==> 3b = 15
Dividing both sides by 3 we get:
b =5
a + c = 2b
a+ c = 10
a = 10 -c ..........(2)
We know that"
(a-b) = (b-c)
==> a > b+c
==> a > 5 + c
==> 10 -c > 5 +c
==>5 > 2c
==> 2.5 > c
As c is an odd number so c will be equal to 1
c = 1
a = 10 -1
a = 9
The three digit number = 951
The hundred digit is greater than the sum of the tens and ones digits
i hope it will help you!
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