(x²+x)(x²+5x+6) = x^4 + 6x³ + 11x² + 6x + 1 ≥0
f(x) = x^4 + 6x³ + 11x² + 6x + 1
f'(x) = 4x³ + 18x² +22x +6
racines x1 = -0,301 x2 = -1,5 x3 = -2,618
variations
x -2,62 -1,5 -0,3
f'(x) - 0 + 0 - 0 +
f(x) -inf \ 0 / \ 0 /
on voit que cette fonction st toujours positive
Answer:
Step-by-step explanation:
Answer:
x+1 meters
Step-by-step explanation:
Area = Length * Width
x^2 - 6x - 7 = length * (x-7)
x^2 + x - 7x - 7 = length * ( x-7)
x*(x+1) - 7*(x+1) = length * (x-7)
(x-7)*(x+1) = length * (x-7)
x+1 = length [for (x-7) not equal 0]
Answer:
2H2S (g) + 3O2 (g) → 2H2O (l) + 2SO2 (g)
Calculate ΔH° from the given data. Is the reaction exothermic or endothermic?
ΔH°f (H2S) = -20.15 kJ/mol; ΔH°f (O2) = 0 kJ/, mol; ΔH°f (H2O) = -285.8 kJ/mol; ΔH°f (SO2) = -296.4 kJ/mol
First let's do parentheses. 1*10^-6 = .000001. Now divide that by one it equals the same thing. Now you need to multiply that by 45612.21. That equals 0.04561221μ
