3a - 1 = 12
+1 +1
—————-
3a = 13
—- ——
3 3
—————
A=4 1/3
Given:
The function, f(x) = -2x^2 + x + 5
Quadratic equation: 0 = -2x^2 + x +5
where a = -2
b = 1
c = 5
The discriminate b^2 - 4ac = 41
To solve for the zeros of the quadratic function, use this formula:
x = ( -b +-√ (b^2 - 4ac) ) / 2a
x = ( 1 + √41 ) / 4 or 1.85
x = ( 1 - √41 ) / 4 or -1.35
Therefore, the zeros of the quadratic equation are 1.85 and -1.35.
Answer:
Your question is a little unclear. If you are just trying to factor x² + 121, it's prime. (can't be factored using real numbers).
Step-by-step explanation:
The difference of two squares is a special form. a² - b² = (a+b)(a-b).
But, the sum of two squares is prime. a²+ b² cannot be factored.
Your answer is x = 7 – 2y
Answer:
Step-by-step explanation:
I’m in middle school
