Answer:
Apply the sine theorem in triangle ABC:
sin C = AB/AC = 4/5
=> C = arcsin(4/5) = 53.13 deg
As shown in picture, AB//CD. Using the same side interior angles theorem:
=> angle BCD = angle ABC = 90 deg
=> angle ACD = 90 - angle ACB = 90 - C = 90 - 53.13 = 36.87 deg
Apply the cosine theorem in triangle ACD:
cos C = AC/CD
=> CD = AC/cos C = 5/cos(36.87) = 5/0.8 = 6.25
=> Option C is correct
Hope this helps!
:)
Answer:
2950
Step-by-step explanation:
Answer:

Step-by-step explanation:
First find the <em>rate of change</em> [<em>slope</em>]:


Then plug these coordinates into the Slope-Intercept Formula instead of the <em>Point-Slope Formula</em> because you get it done much swiftly. It does not matter which ordered pair you choose:
15 = −1⅕[−10] + b
12

If you want it in <em>Standard Form</em>:
y = −1⅕x + 3
+1⅕x + 1⅕x
______________
[We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it.]
5[1⅕x + y = 3]

_______________________________________________
−3 = −1⅕[5] + b
−6

y = −1⅕x + 3
+1⅕x + 1⅕x
______________
[We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it.]
5[1⅕x + y = 3]

** You see? I told you it did not matter which ordered pair you choose because you will always get the exact same result.
I am joyous to assist you anytime.