Answer:
1,787 for intreast and 1772
explanation:
that is from a reliable web site calculator
Answer:
48
Step-by-step explanation:
<h3>
Answer: Choice B</h3>
With matrix subtraction, you simply subtract the corresponding values.
I like to think of it as if you had 2 buses. Each bus is a rectangle array of seats. Each seat would be a box where there's a number inside. Each seat is also labeled in a way so you can find it very quickly (eg: "seat C1" for row C, 1st seat on the very left). The rule is that you can only subtract values that are in the same seat between the two buses.
So in this case, we subtract the first upper left corner values 14 and 15 to get 14-15 = -1. The only answer that has this is choice B. So we can stop here if needed.
If we kept going then the other values would be...
row1,column2: P-R = -33-16 = -49
row1,column3: P-R = 28-(-24) = 52
row2,column1: P-R = 42-25 = 17
row2,column2: P-R = 35-(-30) = 65
row2,column3: P-R = -19-36 = -55
The values in bold correspond to the proper values shown in choice B.
As you can probably guess by now, matrix addition and subtraction is only possible if the two matrices are the same size (same number of rows, same number of columns). The matrices don't have to be square.
The minimum cost to produce the product is $7.
What are functions?
- A function from a set X to a set Y allocates exactly one element of Y to each element of X.
To determine the minimum cost:
We have to determine the minimum cost of producing this product.
Since
.
Now, consider the equation
.
Dividing the above equation by 5, we get

Now, considering the coefficient of 'x', dividing it by '2' and then adding and subtracting the square of the number which we got after dividing.
Since the coefficient of 'x' is 14, and half of 14 is '7'.
So, adding and subtracting from the above equation.

Now, we have to determine the minimum cost to produce the product.
Since
.

Now, let f'(x)=0

Therefore, x=7
Now, consider which is greater than 0.
Therefore, x= 7 is the minimum cost.
Know more about functions here:
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